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Likurg_2 [28]
3 years ago
6

A number cube with the numbers 1 through 6 is rolled. Find the given probability

Mathematics
2 answers:
Simora [160]3 years ago
4 0

\huge\red{\mid{\underline{\overline{\textbf{ANSWER}}}\mid}}

D)\frac{5}{6}\;is \: your \: answer

sesenic [268]3 years ago
4 0

Answer:

5/6

Step-by-step explanation:

I had this question and it was correct.

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Are z³ and 3z equivelent?explain​
salantis [7]
Yes because you are multiplying 3 z’s and also 3z’s
7 0
4 years ago
I don't understand how to solve?
Kobotan [32]
Ok u have a phone and call 911 and say I don't know to solve can u help me
6 0
4 years ago
What is the image of (-9,6) after a dilation by a scale factor of 4 centered at the<br> origin?
myrzilka [38]

Answer:

<em>( - 36, 24 ) </em>

Step-by-step explanation:

(- 9, 6) ------> ( - 9×4, 6×4) = <em>( - 36, 24 )</em>

3 0
3 years ago
A recipe calls for 2 1/2 cups of sugar. You have 2 2/3 cups of sugar. Do you have enough sugar? If not, how much more sugar is n
Karo-lina-s [1.5K]

The difference between the cups of sugar is 1/6, hence you have enough sugar.

<h3>Difference and sum of fractions</h3>

Fractions are written as a ratio of two integers, For instance, a/b is a fraction where a and b are integers.

According to the question, a recipe calls for 2 1/2 cups of sugar. If have 2 2/3 cups of sugar;

Difference of cups of sugar = 2 2/3 - 2 1/2

Convert to improper fraction

Difference = 8/3 -  5/2

Difference = 16-15/6

Difference = 1/6

Since the difference between the cups of sugar is 1/6, hence you have enough sugar.

Learn more on fraction here: brainly.com/question/17220365

#SPJ1

3 0
2 years ago
I WILL GIVE BRAINLIEST
shusha [124]

Answer:

x = -3

Step-by-step explanation:

y\geq -\frac{2}{3} x-3\\&#10;y\leq 3x+8

-\frac{2}{3} x-3=3x+8

Add 2/3 x to both sides:  -3=\frac{11}{3}x+8

Subtract 8 from both sides: -11=\frac{11}{3}x

Multiply both sides by 3:  -33=11x

Divide both sides by 11:  x=-3

Therefore, point of intersection between both lines is at point (-3, -1)

5 0
2 years ago
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