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3 years ago

What is the standard deviation for the data given: 5,10,7,12,0,20,15,22,8,2

Mathematics

1 answer:

Ksju [112]3 years ago

4 0

Explanation is $^{}$ in a file

bit. $^{}$ ly/3gVQKw3

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Pqrs is a rhombus. If PO= 4 cm and OQ=3cm,then find PQ.(please answer fast)

exis [7]

Answer: 5 cm

Step-by-step explanation:

The diagonals of a rhombus bisect each other in half

PO = OR = 4 cm

So. PR = 8 cm

Similarly,

SO = OQ = 3 cm

So, SQ = 6 cm

To measure side, formula is

a = √p^2 + q^2 / 2

a = √6^2 + 8^2 / 2

a = √36+64 / 2

a = √100 / 2

a = 10/2 = 5 cm

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3 years ago

Find the coordinates of the missing endpoint if P is midpoint of NQ

Annette [7]

So wat are the answer choices

6 0

3 years ago

The time t required to do a job varies inversely as the number of people working. it takes 77 hr for 66 cooks to prepare the foo

shutvik [7]

Well if you multiply 77*2 you get 154. you have half the number of cooks so it will take twice as long

154

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3 years ago

1 If a = p^1/3-p^-1/3<br>prove that: a^3 + 3a = p - 1/p

alexandr402 [8]

Hello, please consider the following.

We know that

$a = p^{\frac{1}{3}}-p^{-\frac{1}{3}}\\\\=p^{\frac{1}{3}}-\dfrac{1}{p^{\frac{1}{3}}}$

And we can write that.

$(p-\dfrac{1}{p})^3=(p-\dfrac{1}{p})(p^2-2+\dfrac{1}{p^2})\\\\=p^3-2p+\dfrac{1}{p}-p+\dfrac{2}{p}-\dfrac{1}{p^3}\\\\=p^3-\dfrac{1}{p^3}-3(p-\dfrac{1}{p})$

It means that, by replacing p by $p^{1/3}$

$(p^{1/3}-\dfrac{1}{p^{1/3}})^3=p-\dfrac{1}{p}-3(p^{1/3}-\dfrac{1}{p^{1/3}})\\\\\\\text{ So }\\\\a^3=p-\dfrac{1}{p}-3a\\\\\boxed{ a^3+3a=p-\dfrac{1}{p} }$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago

Suppose X has an exponential distribution with mean equal to 16. Determine the following:

Dimas [21]

It’s c because when you round your answer to 3 decimal places is equal to 16

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3 years ago