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n200080 [17]
3 years ago
9

1. Create an expression, containing at least two variables, that can be factored using the sum of two cubes identity.

Mathematics
1 answer:
podryga [215]3 years ago
8 0
Remember that the sum of tow cubes identity is: a^3+b^3=(a+b)(a^2-ab+b^2)
So, to create our expression<span>, containing at least two variables, that can be factored using the sum of two cubes, we just need to replace </span>a and b with tow monomials with a different variable:
a=x and b=y
Lets replace those values in our identity: 
x^3+y^3

Now that we have our expression, lets factor it using the sum of two cubes identity:
x^3+y^3=(x+y)(x^2-xy+y^2)
To verify if the factored form of our expression (right hand side) is equivalent to the original form (left hand side), we are going to expand the right hand side:
x^3+y^3=(x+y)(x^2-xy+y^2)
x^3+y^3=x^3-x^2y+xy^2+x^2y-xy^2+y^3
x^3+y^3=x^3+x^2y-x^2y+xy^2-xy^2+y^3
x^3+y^3=x^3+y^3

Since both sides of the equation are equal, we can conduce that the factored form of our expression is equivalent to the original expression.

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koban [17]

Answer:

x = -223/11 = -20.273

Step-by-step explanation:

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Step 2: Simplify 33/5

Step  3  :

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Step  4: Simplify: 1/2

Step  5  :  see below

Step  6  :  see below

Pulling out like terms/factors

Step  7 : Simplify: 51/2

Step 8:  Simplify: 22/5

Step 10: Simplify: 43/10

Step  9  :

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Step  11  :

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Done.

Hope this helps.

7 0
3 years ago
The ground temperature at an airport was 10 degree temperature dropped 5 degrees for every 1000m above the ground. What was the
Mamont248 [21]
The ground temperature started at 10 degrees.
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3 0
4 years ago
Given<br> the<br> function<br> f(x)= 3(x-2)² + 5, what<br> is<br> f(-1)?
motikmotik

Answer:

32

Step-by-step explanation:

f(x)= 3(x-2)² + 5

Let x = -1

f(-1)= 3(-1-2)² + 5

Parentheses first

f(-1) = 3(-3)^2 +5

Exponents

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Multiply

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Add

f(-1) = 32

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