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3 years ago

7b+8<100 how many books can Brian buy without overspending

Mathematics

2 answers:

Semenov [28]3 years ago

6 0

Answer:

Step-by-step explanation:

7b + 8 < 100

subtract 8 from both sides

7b < 92

divide both sides by 7

b < 92/7 ≅ 13.1

Brian can buy at most 13 books.

Kamila [148]3 years ago

4 0

Answer: You have to plug in the numbers.

So first let's plug in 13. 7*13+8=99

Now 15. 7*15+8=113

Now 18. 7*18+8=134

Lastly 20. 7*20+8=148

The answer is 13.

Step-by-step explanation:

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A 98% confidence interval for a proportion is found to be (0.62, 0.68).

Vilka [71]

Answer:

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3 0

2 years ago

Need the answer asapp with the working out please thanks :)

patriot [66]

Hi,

The two numbers should be 12 and 30. 12=2x2x3 while 30=2x3x5.

Their HCF is 2x3=6 and their LCM is 2x3x2x5. Because of their HFC, we know that they are both multiple of 6. Also, the question says they both are GREATER than 6, so they can’t be 6 but are 6 times “something”. Thanks to the LCM, we know that “something” is equal to 2 for the first number and to 5 for the second one, the numbers hence being 12 and 30.

I hope this helps. If I was not clear enough or if you’d like further explanation please let me know. Also, English is not my first language, so I’m sorry for any mistakes.

7 0

3 years ago

Expand (2 + a)9 using Pascal’s triangle.

Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

1 $(A + B) ^ 0$ = 1

1 1 $(A +B ) ^ 1 = 1A + 1B$

1 2 1 $(A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2$

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1 9 36 84 126 126 84 36 9 1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

$1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B$

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

$1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9$