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Alecsey [184]
3 years ago
13

Simplify (6 5x) (7x 3)

Mathematics
1 answer:
Allisa [31]3 years ago
6 0
It would be 7x times 6 = 42 and then 3 times 5 = 15 then add 57x
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One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
Jason's mom drove at 100km/hr for a 160km trip.how much longer would the trip have taken if she had driven at 90km/hr
kondor19780726 [428]
We use the formule: t=S/v. So:
+ t1= 160/100 = 8/5 hrs = 5760''
+ t2= 160/90 = 16/9 hrs = 6400''

=> t2-t1= 6400 - 5760 = 640'' = 10'40''


3 0
3 years ago
Convert 2/50 to percent
vodomira [7]

Answer: 4%

Step-by-step explanation: 50 x 2 = 100

2x2=4 4/100 or 4%

8 0
3 years ago
Read 2 more answers
Plz answer me will mark as brainliest read full question
Musya8 [376]

Answer:83 -->17-->103-->43-->7-->1

Have a good day

6 0
3 years ago
PLZ ANSWER IT HARD FOR ME
creativ13 [48]
First you have to find a common denominator between all the fractions which would be 12 for the first week it would be reduced to 6 3/12 and the second 4 8/12 both added together would be 10 and 11/12 so the equation would be 15 4/12 - 10 11/12 which would be 4 5/12.
6 0
3 years ago
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