Answer:
wedsadwadswds
Step-by-step explanation:
f(x) = sqrt(x)
f(17) = sqrt(17)
it is close to sqrt(16)=4
so to the nearest integer
f(17) = 4
Option D:
ΔCAN ≅ ΔWNA by SAS congruence rule.
Solution:
Given data:
m∠CNA = m∠WAN and CN = WA
To prove that ΔCAN ≅ ΔWNA:
In ΔCAN and ΔWNA,
CN = WA (given side)
∠CNA = ∠WAN (given angle)
NA = NA (reflexive side)
Therefore, ΔCAN ≅ ΔWNA by SAS congruence rule.
Hence option D is the correct answer.
Not quite sure what you mean by brackets, but you can get the solution to this equation in a few steps:
<span>(-2x - 1)</span>² <span>= 0 ... square root both sides to eliminate the squared binomial
</span>√(-2x - 1)² = √0 ... simplify; the square is canceled out and the root of 0 brings you back to 0
-2x - 1 = 0 ... solve like a two-step equation
-2x = 1
x = -1/2 is your x-value.
