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2 years ago

HELP ME WITH THIS QUESTION PLEASE

Mathematics

1 answer:

Shkiper50 [21]2 years ago

8 0

Answer:

Step-by-step explanation:

1. 7x + 4

2. 3x - 2

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Select all the expressions equivalent to: (4^5)⋅4^3 Group of answer choice 2^14 4^12 2^16 16^8 4^8 16^4

kumpel [21]

Answer:

Choices given as $2^{16}, 4^8$ and $16^4$ are correct.

Step-by-step explanation:

Given expression is,

$(4^5)(4^3)$

By applying law of exponents in the given expression,

$(4^5)(4^3)=4^{5+3}$

$=4^8$

$(4^5)(4^3)=(2^2)^5(2^2)^3$

$=(2^{2\times 5})(2^{2\times 3})$

$=2^{10}\times 2^6$

$=2^{16}$

$=(2^4)^4$

$=(16)^4$

Therefore, choices given as $2^{16}, 4^8$ and $16^4$ are correct.

4 0

3 years ago

What is the equation of the line that is perpendicular to f(x) and passes through the point (4, –6)? a.4x + 3y = –2 b. 3x + 4y =

user100 [1]

Answer:

Step-by-step explanation: because its even

4 0

3 years ago

If you do all you'll get brainliest

Flura [38]

The two equations:
Daisy’s: y = 4x + 14
Donald’s: y= 2x + 26

The point of intersection is (6, 38)
This point refers to how many of passengers it will take for both equations to have have the same cost output.

Daisy’s deal is better if you have less than 6 passengers. We can tell because the line for the equation is lower than Donald’s line. Donald’d deal will be better if you have more than 6 passengers since the line is lower than daisy’s deal.

7 0

2 years ago

Which ratio correctly compares 120 cm to 80 mm?

bixtya [17]

120 cm=120 cm*(10 mm/1cm)=1200 mm,

Ratio: 1200 mm / 80 mm=15/1

Answer:

C. 15 to 1

3 0

3 years ago

Best answer gets brainliest

patriot [66]

Question below!

what do you need in order to construct in order to find a point/location that has the same distance away from 2 or more other points

Answer:

Hi, There! Mika-Chan I'm here to help! :)

To find the distance from a point to a line, first find the perpendicular line passing through the point. Then using the Pythagorean theorem, find the distance from the original point to the point of intersection between the two lines.

Hope this Helps!

3 0

3 years ago