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kakasveta [241]
2 years ago
5

Whats the answer? F DC bhgffjyfvjigfbj

Mathematics
2 answers:
Vesnalui [34]2 years ago
8 0

Answer:

10

Step-by-step explanation:

we distribute the - to the -7 and get 7

then we add them 3+7=10

docker41 [41]2 years ago
6 0

Answer:

the difference is 10. I hope this helps

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evaluate if s equals 5 and 2 equals 7 3s^2 +t^2 -3 please show how you got your work I will get brainiest
iragen [17]

3 {(5)}^{2}  + ( {7)}^{2}  - 3 \\ 3(25) + 49 - 3 \\ 75 + 49 - 3 \\  = 121
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What is negative 8 times negative 8
Vlad1618 [11]
-64 use a calculator

3 0
3 years ago
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A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat
sladkih [1.3K]
<h2>Question: </h2>

A shopkeeper bought wheat for rs.35000. Due to leakage in the godown 1/7 of the total wheat was spoiled. He sold the good wheat at a gain of 10% and the spoiled when at a loss of 25%. Find his total gain or loss per cent.

Answer:

<h2>5%</h2>

<h2>step by step answer:</h2>

In the question we are given a shopkeeper or bought wheat for Rs. 35000. Now, due to leakage 17 of the total wheat is spoiled. Now, he sold the good wheat at 10% gain and the bad wheat at 25% loss. We need to find the total gain/loss percent.

According to the problem, the total cost of wheat is Rs. 35000.

Now, let us find the cost price of the spoiled wheat.

So, the cost of spoiled wheat is 17×Rs35000 which is equal to Rs. 5000.

Hence, the cost price of spoiled wheat is Rs 5000.

As we know that the spoiled wheat was sold at 25% loss, so we can say that if the cost price is considered as 100% so the selling price is considered as (100−25)% or 75%.

So, we got the selling price of spoiled wheat is 75100×5000=Rs3750

So, the cost price of spoiled wheat is Rs.5000 and selling price of spoiled wheat is Rs.3750.

Now, let us find the cost price of the good wheat.

Now, we will consider the good quality of wheat whose cost price is Rs(35000−5000) which is Rs. 30000.

Hence, the cost price is Rs. 30000.

As we know good quality wheat was sold at 10% gain so we can say that, if the cost price is 100% then the selling price will be (100+10)% or 110% .

Hence, the selling price of good quality wheat is 110100×Rs30000 which is Rs. 33000.

So, the cost price of good quality wheat is Rs. 30000 and selling price is Rs. 33000.

Let us find the total selling price of the wheat that the shopkeeper bought.

Now the total selling price of the wheat is Rs.3750+Rs.30000=Rs.36750.

Hence Profit = Total selling price − Total cost price

profit =Rs.36750−Rs.35000

=Rs.1750

profit %

=profitcost price×100%.

=175035000×100%.

=5%.

<h2>So, total profit is 5%.</h2>
6 0
2 years ago
Read 2 more answers
GIVING BRAINLIESTTTTT
andreev551 [17]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

# Contracting parallel lines

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2. Place the pin of the compass at point C and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

# Constructing a perpendicular line through a point on the line

- Given line AB and point P lies on it

1. Place your compass pin at P and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3. Place the compass pin on point C and draw a small arc above the line

4. Without changing the distance of the compass place the compass pin on point D and draw another arc intersects the arc from C at point E

5. Using a straightedge, join P and E where PE is perpendicular to AB

* Lets find the same steps in the constructions

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  "Place the compass on a point on the original line"

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cluponka [151]
58 and 22 is the answer.
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