Answer: The distance is 15
Step-by-step explanation:
To find the distance between L and Y find the difference in the x and y coordinates then square them and add them to find their square root.
-7-5= -12
0-9 = -9
12^2 + 9^2 = d^2 where d is the distance
144 + 81 = d^2
225 = d^2
d=
d= 15
Answer:
The distance of the helicopter from the bristol is approximately 1<u>2.81 miles</u>
Step-by-step explanation:
Given:
Helicopter flies 10 miles east of bristol.
Then the helicopter flies 8 miles North before landing.
To find the direct distance between the helicopter and bristol.
Solution:
In order to find the distance of the helicopter from the bristol before landing, we will trace the path of the helicopter
The helicopter is first heading 10 miles east of bristol and then going 8 miles due north.
On tracing the path of the helicopter we find that the direct distance of the helicopter from the bristol is the hypotenuse of a right triangle formed by enclosing the path of the helicopter.
Applying Pythagorean theorem to find the hypotenuse of the triangle.
Taking square root both sides.
Thus, the distance of the helicopter from the bristol is approximately 12.81 miles
The value of each measure based on the incenter is illustrated below.
<h3>What is incenter?</h3>The incenter of a triangle is the point of intersection of all the three interior angle bisectors of the triangle. This point is equidistant from the sides of a triangle.
Angle ARU = 40 degree
Length of AU = 20
Angle QPA = 35 degree
Since, AR is angle bisector of angle URK.
So, ∠ARU = ∠ARK = 40 degree
Since, incenter point is equidistant from the sides of a triangle.
So, AT = AU = AK = 20
Since, PA is angle bisector of angle QPU.
So, ∠QPA = ∠UPA
3x + 2 = 4x - 9
4x - 3x = 9 + 2
x = 11
Substituting value of x in angle 3x + 2
We get, ∠QPA = 3(11) + 2 = 35°
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