Step-by-step explanation:
Select all of the following that are quadratic equations.
x² + 3x - 5 = 0 ✓
x² - x = 3x + 7 ✓
5x - 7 = 0 X
7x² + 14x = 0 ✓
x³ - 3x² + 1 = 0 X
x - 5 = 9x + 7 X
What is quadratic equations?
Quadratic equations is a equation that has a general form like "ax² + bx = c"
For example :
x² + 3x - 5 = 0
x² + 3x = 5
x² → ax²
3x → bx
5 → c
Answer:
sec(theta°)cos(theta°) = 1
Step-by-step explanation:
given data
(theta°) = 225
to find out
sec(theta°)cos(theta°)
solution
as we know that given equation
(theta°) = 225
cos(theta°) will be
cos(225°) = -0.7071 .................................1
so we know
sec(theta°) =
..............2
so put here value of cos(theta°)
sec(theta°) =
sec(theta°) = - 1.4142
so
sec(theta°)cos(theta°) = -0.7071 × ( - 1.4142 )
sec(theta°)cos(theta°) = 1
so answer is sec(theta°)cos(theta°) = 1
For this case, the first thing we must do is define variables.
We have then:
x: number of minutes
y: final temperature
We write then the equation that models the problem:

For y = 20 we have:

Clearing x:
Answer:
The temperature of the water will be 20 degree celcius after 150 minutes
(-36x^4y+144x²y^6) / (-4x²y) =
36xy*(x³+4xy^5) / (-4x²y) =
-9*(x³+4xy^5) / x
Answer:
(2,0)
Step-by-step explanation: