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sergey [27]
3 years ago
12

Help! I'm a little stumped when it comes to variables in matrices. An explanation would be super rad!

Mathematics
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

30

Step-by-step explanation:

To find the determinant of a 3x3 matrix, you can use this method. (See picture.)

Start with the first number in the top row, and block off the row and column.  A 2x2 matrix will be left.  Find the determinant of this 2x2 matrix, and multiply it by the number in the top row.

Repeat for the other two numbers in the top row.  Add the first result, subtract the second, and add the third.

det A = -2 [(3)(-5) − (a)(0)] − 2 [(0)(-5) − (a)(0)] + b [(0)(0) − (3)(0)]

det A = -2 (3)(-5) − 0 + 0

det A = 30

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In ΔCDE, the measure of ∠E=90°, ED = 28, CE = 45, and DC = 53. What ratio represents the tangent of ∠C?
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3 years ago
Y=1/6x+5 in standard form using integers.
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4 years ago
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Can anyone help me with this?
aleksklad [387]
With the given table, this isn't possible without resorting to an approximation of an approximation.

The interval [0,8] can be partitioned as [0,2]\cup[2,4]\cup[4,6]\cup[6,8], with the respective midpoints of t\in\{1,3,5,7\}. So the average temperature is given exactly by the definite integral

\displaystyle\frac1{8-0}\int_0^8f(t)\,\mathrm dt

which is approximated by

\displaystyle\frac14\sum_{t\in\{1,3,5,7\}}f(t)=\dfrac{f(1)+f(3)+f(5)+f(7)}4

where the coefficient \dfrac14 comes from the fact that each subinterval has length 2, and so \dfrac28=\dfrac14.

However, you don't know the values of f(t) at these points. At best you can approximate them, perhaps by interpolating f(t) (you have the details needed to do it, at any rate).

Are you sure you're not supposed to find the average temperature over the entire set of observation times, i.e. over 0\le t\le16?
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3 years ago
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