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omeli [17]
3 years ago
7

Calcuate the distance Tom rides his bike if he rides 5\6 mile of each 5 days

Mathematics
2 answers:
defon3 years ago
8 0

The multi-stage fitness test (MSFT), also known as the beep test, bleep test, PACER (Progressive Aerobic Cardiovascular Endurance Run), Pime, they are cautioned. A second caution ends the test for that runner. The number of shuttles completed successfully is recorded as the score of that runner. The score is recorded in Level.Shuttles format (e.g. 9.5).

Anna [14]3 years ago
4 0

Answer: 4

Step-by-step explanation:

5/6*5= 4.1<u>6</u>7=4

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Suppose that a monopolist
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Answer:

The monopolist's net profit function would be:

N(y)=198\,y\,-\,2.5\,y^2

Step-by-step explanation:

Recall that perfect price discrimination means that the monopolist would be able to get the maximum price that consumers are willing to pay for his products.

Therefore, if the demand curve is given by the function:

P(y)=200-2y

P stands for the price the consumers are willing to pay for the commodity and "y" stands for the quantity of units demanded at that price.

Then, the total income function (I) for the monopolist would be the product of the price the customers are willing to pay (that is function P) times the number of units that are sold at that price (y):

I(y)=y*P(y)\\I(y)=y\,(200-2y)\\I(y)= 200y-2y^2

Therefore, the net profit (N) for the monopolist would be the difference between the Income and Cost functions (Income minus Cost):

N(y)=I(y)-C(y)\\N(y)=(200\,y-2y^2)-(2y+0.5y^2)\\N(y)=198\,y\,-\,2.5\,y^2

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2 years ago
2,10,50 geometric sequence
ValentinkaMS [17]
The next three are; 250, 1,250, and 6,250
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2 years ago
Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
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