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torisob [31]
2 years ago
7

Graph the linear equation 4x+9y=36 solving for y

Mathematics
1 answer:
rjkz [21]2 years ago
8 0

Answer:

y=4-4/9x x=9-9/4y

Step-by-step explanation:

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The temperature changed from 7°f at 6pm to -5°f at midnight. What was the difference between the high an low temperatures? Whats
Ronch [10]

Answer:

Difference between high and low temperatures: 12°F

Average change in temperature per hour: 2°F

Step-by-step explanation:

The difference between high and low temperatures was: 7 - (-5) = 12 (°F)

Midnight is 12am, so 6pm to midnight is 6 hours.

The average change in temperature per hour is: 12 / 6 = 2 (°F)

7 0
3 years ago
Evaluate −3w − 6p for w=2 and p = −7
kap26 [50]

-3w-6p when w=2 and p=-7

-3(2)-6(-7)

= -6 + 42

= 36

7 0
2 years ago
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EB bisects ∠RED. Find the measure of ∠BED if ∠REB = 5x – 3 and ∠RED = 8x + 16<br><br>plzzzzzzzzzzz
Allushta [10]

Answer:

this is 52 degrees

Step-by-step explanation:

7 0
2 years ago
On your cell phone bill, you are charged $0.25 for each text you send. What is the dependent variable?
zhannawk [14.2K]

Answer:

The amount of the bill is dependent on the number of texts sent. Let y be the bill amount and x the number of texts. Then x is independent and y is dependent. This is because x can be any non-negative number, but y depends upon it. You cannot find the bill without knowing the number of text messages, right?

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2 years ago
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Does the table represent an exponential function? Explain.
Ede4ka [16]

Answer:

No, because as the x-values are increasing by a constant amount, the y-values are not being multiplied by a constant amount.

Step-by-step explanation:

We have a set of ordered pairs of the form (x, y)

If a function is exponential then the ratio between the consecutive values of y, is always equal to a constant.

This means that:

\frac{y_2}{y_1}=\frac{y_3}{y_2}=\frac{y_4}{y_3}=by1y2=y2y3=y3y4=b

This is: y_2=by_1y2=by1

Now we have this set of points {(-1, -5), (0, -3), (1, -1), (2, 1)}

Observe that:

\begin{gathered}\frac{y_2}{y_1}=\frac{-3}{-5}=\frac{3}{5}\\\\\frac{y_3}{y_2}=\frac{-1}{-3}=\frac{1}{3}\\\\\frac{3}{5}\neq \frac{1}{3}\end{gathered}y1y2=−5−3=53y2y3=−3−1=3153=31

Then the values of y are not multiplied by a constant amount "b"

5 0
3 years ago
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