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Degger [83]
3 years ago
14

Vince weighs 160 pounds, and his friend Nadir weighs 140 pounds. Nadir calculated that his weight on another planet would be abo

ut 56 lb. Approximately what would Vince weigh on the other planet?
Mathematics
2 answers:
slega [8]3 years ago
7 0

Answer:

Honestly, a person wouldn't know unless they knew what the Gravitational pull on the other planet was. But in this case, Vince would be approxematly 64 pounds on the other planet.

Step-by-step explanation:

vlabodo [156]3 years ago
5 0
160/140 = x/56
cross multiply
(140)(x) = (160)(56)
140x = 8960
x = 8960/140
x = 64 lbs <== Vince's weight on the other planet
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How do I simplify this exponent problem???
Nikolay [14]

Hello from MrBillDoesMath!

Answer:

(3/4) a^(-5)b^(-3)c^2


Discussion:  

(18 a^-3b^2c^6)/ (24 a^2b^5c^4) =

(18/24) a^ (-3-2) b^(2-5) c^(6-4) =

                  as  a^-3/a^-2 = a ^ (-3-2) = a^(-5), for examples

(3/4) a^(-5)b^(-3)c^2


Thank you,

MrB

8 0
2 years ago
Simplifying an Expression with the Numerator and the Denominator Raised to a Power
slamgirl [31]

Answer:

The answer to your question is    the second option     \frac{1}{x^{48}y^{36}z^{6}}

Step-by-step explanation:

Expression

                       [\frac{(x^{2}y^{3})^{-2}}{(x^{6}y^{3}z)^{2}}]^{3}

Process

1.- Divide the fraction in numerator and denominator

a) Numerator  

 [(x²y³)⁻²]³ = (x⁻⁴y⁻⁶)³ = x⁻¹²y⁻¹⁸

b) Denominator

 [(x⁶y³z)²]²= (x¹²y⁶z²)³ = x³⁶y¹⁸z⁶

2.- Simplify like terms

a) x⁻¹²x⁻³⁶ = x⁻⁴⁸

b) y⁻¹⁸y⁻¹⁸= y⁻³⁶

c) z⁻⁶

3.- Write the fraction

        \frac{1}{x^{48}y^{36}z^{6}}

6 0
3 years ago
Consider the first 2 terms of the sequence -6, 18,...
____ [38]

Answer:

arithmetic sequence: 24, 42, 66, 90, 114; y = 24x - 30

geometric sequence: -54, 162, -486, 1458, -4374; y = -6(-3)^(x - 1)

Step-by-step explanation:

Arithmetic sequence:

-6, 18, ...

18 - (-6) = 24

18 + 24 = 42

42 + 24 = 66

66 + 24 = 90

90 + 24 = 114

y = -6 + 24(x - 1)

y = -6 + 24x - 24

y = 24x - 30

Geometric sequence:

-6, 18, ...

18/(-6) = -3

18 * (-3) = -54

-54 * (-3) = 162

162 * (-3) = -486

-486 * (-3) = 1458

1458 * (-3) = -4374

y = -6(-3)^(x - 1)

5 0
2 years ago
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Then umbers are 50,51,52
4 0
3 years ago
Which graph shows the correct solution to the linear-quadratic system of inequalities below?
LUCKY_DIMON [66]

Answer:

(the pic)

Step-by-step explanation:

I used a link

8 0
3 years ago
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