A bakery sells 2 croissants for $3 they sold 31 croissants on Monday, how much money did they make
1 answer:
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Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is. 
. 
. 
. The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same. In other words, we cannot add the square root of 4 to the square root of 5. They either both have to be 4 or they both have to be 5. So here's what we have thus far: 
. We can add 
and 
to get 
. That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.