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KonstantinChe [14]
3 years ago
5

Need help please !!!!!!

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0
A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is.  \sqrt{192}= \sqrt{64*3}= 8\sqrt{3}.  \sqrt{80}= \sqrt{16*5}=4 \sqrt{5}.  \sqrt{12288}= \sqrt{4096*3}=64 \sqrt{3}.  The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same.  In other words, we cannot add the square root of 4 to the square root of 5.  They either both have to be 4 or they both have to be 5.  So here's what we have thus far: 8 \sqrt{3}+4 \sqrt{5}+64 \sqrt{3}.  We can add 8 \sqrt{3} and 64 \sqrt{3} to get 72 \sqrt{3}.  That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.
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There are some red and blue balls in a bag of 21 balls and the probability of picking 2 red balls out in a row is 1/14 how many
Over [174]

Answer:

6 red balls

Step-by-step explanation:

The probability in the first pick

6/21

The probability in the second pick (without replacement)

5/20

the requested probability

(6/21)(5/20) = 30/420

simplification

30/420 = 3/42 = 1/14

Hope this helps

8 0
3 years ago
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PLEASE HELP NOW ASAP!!!
IceJOKER [234]

She used the associative property which should only be used with positive numbers (sorry if it isn't the answer you're looking for)

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2 3/4 written as fraction greater than one
sladkih [1.3K]
2 3/4 = 11/4 <=== written as an improper fraction
3 0
3 years ago
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(5x+6xy-4)-(-6x+7xy+2)
Maslowich

Answer: 11x - xy - 6

Step-by-step explanation:

(5x+6xy-4)-(-6x+7xy+2)

5x + 6xy - 4 + 6x - 7xy -2

11x - xy - 6

3 0
3 years ago
Ryan, a baker, measured the weights of cakes baked in each batch at his bakery and found that the mean weight of each cake is 50
denpristay [2]

Answer: Rejecting the mean weight of each cake as 500 gram when H subscript 0 equals 500

Step-by-step explanation:

Given that :

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Alternative hypothesis : Ha < 500

Type 1 Error: Type 1 error simply occurs when we reject the Null hypothesis when the Null is true. Alternatively, type 11 error occurs when we fail to reject a false null hypothesis.

Hence, in the scenario above, a type 1 error will occur when we reject the mean weight as 500 even though the Null hypothesis is True.

6 0
4 years ago
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