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KonstantinChe [14]
2 years ago
5

Need help please !!!!!!

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
5 0
A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is.  \sqrt{192}= \sqrt{64*3}= 8\sqrt{3}.  \sqrt{80}= \sqrt{16*5}=4 \sqrt{5}.  \sqrt{12288}= \sqrt{4096*3}=64 \sqrt{3}.  The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same.  In other words, we cannot add the square root of 4 to the square root of 5.  They either both have to be 4 or they both have to be 5.  So here's what we have thus far: 8 \sqrt{3}+4 \sqrt{5}+64 \sqrt{3}.  We can add 8 \sqrt{3} and 64 \sqrt{3} to get 72 \sqrt{3}.  That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.
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h = V/lw

Step-by-step explanation:

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What is the angle of rotation of the figure above? Assume that the center of rotation is the origin.
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SOMEONE PLS HELP ME ON ALL THESE ASAP!!!!!​
natulia [17]

Answer:

4Q a). angle1=55°

angle2=23°

angle3=63°

angle4=125°

5Q. x=35°

6Q. y=15°

8Q. C. 28°

9Q. Yes, they are congruent by S.S.S. congruence

10Q. A.A.S.

11Q. S.S.S.

12Q. Not possible

13Q. S.A.S.

14Q. S.S.S.

15Q. 66°

16Q. 24°

I hope it will be useful.

Step-by-step explanation:

7Q. angle1=angle3 (Alternate Interior Angles)

angle2=angle4 (A.I.A.)

angleXWZ=angleXYZ (opposite angles of a parallelogram)

By A.A.A. congruence criteria, they are congruent.

8Q. Hint: Make the diagram first!

AngleC is halved since M is the mid-point.

angleA=angleB (Property of an isosceles triangle)

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