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2 years ago

Find the value of the sum ∑j=131(6j2−7j+4)

Mathematics

2 answers:

Sveta_85 [38]2 years ago

7 0

I don’t know but I really need answers

Mashutka [201]2 years ago

7 0

I think that’s sum numbers like 1+3

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Please answer this correctly without making mistakes

aleksandrvk [35]

Answer:

The distance between the art gallery and the office supply store is 42 miles

Step-by-step explanation:

Notice that the segment that joins the office store with the art gallery, has a length that equal the distance between the art gallery and the bank, plus the distance between the bank and the office supply store. That is;

32.1 mi + 9.9 mi = 42 mi

7 0

3 years ago

Read 2 more answers

Factor the trinomial by grouping.<br> 9x^3 - 3x^2 -30x

katen-ka-za [31]

Answer:

3x(3x+5)(x-2)

Step-by-step explanation:

$9x^3-3x^2-30x= \\\\3x(3x^2-x-10)= \\\\3x(3x^2+5x-6x-10)= \\\\3x(x(3x+5)-2(3x+5))= \\\\3x(3x+5)(x-2)$

Hope this helps!

4 0

3 years ago

Use the Ratio Test to determine whether the following series converges or diverges.

Dafna1 [17]

Answer:

Find the interval of convergence of the following series

Possible Answers:

(4,6)

[4,6)

(4,6)

[4,6]

Correct answer:

(4,6)

Explanation:

Step-by-step explanation:

Find the interval of convergence of the following series

Possible Answers:

(4,6)

[4,6)

(4,6)

[4,6]

Correct answer:

(4,6)

Explanation:

8 0

11 months ago

Pls help me solve pls show how you got the answer

sergij07 [2.7K]

Answer:

48 length units

Step-by-step explanation:

area of each squre = 9

side length of each square = sqrt(9) = 3

Length of each side of grid = 4*3 = 12

Perimeter of grid = 4 sides = 4*12 = 48 length units

7 0

3 years ago

Read 2 more answers

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago