Can you check your question please
(2×3)^2
=6^2
=36
5^2
=25
3p + 7c = p....subtract 3p from both sides
7c = p - 3p
7c = - 2p ....now divide both sides by 7
c = -2/7p <==
The stiffness of one short spring is 13500 N/m
<em><u>Solution:</u></em>
We are given a chain with number of spring N = 30 and linked end to end ( in series) and stiffness of this chain is 450 N/m
We have to find the stiffness of one short spring
The springs are identical, which means they have same stiffness
<em><u>The stiffness of one spring in series is given as:</u></em>
Where,
N is the number of springs
is the stiffness of one spring
is the stiffness of this chain
Substituting,
Therefore,
Thus the stiffness of one short spring is 13500 N/m
Answer:
x = 122
Step-by-step explanation: