PLZ HELP ME! SUPER URGENT!

Mathematics

1 answer:

puteri [66]2 years ago

8 0

1.-3,-1 for f and h and 1,4
2.They are Symetrical

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8 Line in the xy-plane contains points from each of Quadrants II, III, and IV, but no points from Quadrant I. Which of the follo

iren2701 [21]

Answer:

The correct option is D.

Step-by-step explanation:

The slope of a line is the change in y with respect to x.

$m=\frac{y_2-y_1}{x_2-x_1}$

If the slope of a line is undefined it means it is a vertical line and a vertical line can not passes through three quadrants. So, option A is incorrect.

If the slope of a line is 0 it means it is a horizontal line and a horizontal line can not passes through three quadrants. So, option B is incorrect.

If the slope of a line is positive it means the value of y increases as x increases.

Since it is an increasing line, therefore after a certain period both x and y will positive. It means the line will passes through first quadrant. So, option C is incorrect.

If the slope of a line is negative it means the value of y decreases as x increases. It can passes through each of Quadrants II, III, and IV.

Therefore the correct option is D.

6 0

2 years ago

1. Use the graph of the rational function

Mrrafil [7]

Answer:

As $x \to -3^{+}, f(x) \to -\infty$

Step-by-step explanation:

Given:

From the graph, we can conclude that:

The function has vertical asymptotes at $x=-3\ and\ x=2$

The function has horizontal asymptote at $f(x)=0$

Vertical asymptotes are those values of 'x' for which the functions tends towards infinity. Horizontal asymptote is the value of the function as the 'x' value tends to infinity.

Now, as $x \to -3^{+}$ means the right hand limit of the function at $x=-3$

From the graph, the right hand limit is the right side of the asymptote of the function at $x = -3$ . The right side shows that the function is tending towards negative infinity.