Question

A person invested $3,500 in an account growing at a rate allowing the money to double every 15 years. How long, to the nearest tenth of a year would it take for the value of the account to reach$7,700?

Answer 1

Answer:

30 years and a half

Step-by-step explanation:

well let's just say 3.5k x hmm 2? at an estimate and that will get us to 7000.. so in order to get to 7000 we have to wait 15 years which is 30 years and a half. From Xthermyx. A brainly user.

Answer 2

Answer:

$t = 17.1$

Step-by-step explanation:

$y = a(2) ^{ \frac{t}{d} }$

$y = 7700 \: \: a = 3500 \: \: d = 15$

$\frac{7700}{3500} = \frac{3500(2) ^{ \frac{t}{15} } }{3500}$

$2.2 = { 2}^{ \frac{t}{15} }$

$\frac{ log(2.2) }{ log(2) } = \frac{t}{15}$

$1.1375352 = \frac{t}{15}$

$15(1.13750352) = t$

$17.062552856 = t$

$t = 17.1$