3x + 5 = 20
x = 5
Hope this helps
The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
Read more about combination at:
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Answer:
x = 9.7
Step-by-step explanation:
Reference angle (θ) = 68°
Opposite = 24
Adjacent = x
Apply, the trigonometric function, TOA which is:

Plug in the values

Multiply both sides by x

Divide both sides by tan 68

x = 9.69662942
x = 9.7 (nearest tenth)
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