Ask question

Ask question

All categories

erma4kov [3.2K]

2 years ago

10

1) the entrance way to the presidio is a rectangle topped by a half circle arch that is 3.2m wide. If the ratio of the area of t

he rectangle to the area of the arch is approximately 3:1, what it the height of the rectangular entranceway?

1 answer:

alexandr402 [8]2 years ago

6 0

The answer to the height of the thing is 4.2

You might be interested in

A quadrilateral has two angles that measure 120° and 140°. The other two angles are in a ratio of 2:3. What are the measures of

Furkat [3]

40 degrees and 60 degrees

8 0

2 years ago

Find (f/g) (x) for the functions provided: ƒ(x) = x3 − 27, g(x) = 3x − 9

AnnZ [28]

Answer:

$(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)$

Step-by-step explanation:

We have been given that

$f(x)=x^3-27,g(x)=3x-9$

We can use the formula for difference of cubes to simplify the function f(x)

difference of cubes - $a^3-b^3=(a-b)(a^2+ab+b^2)$

$f(x)=x^3-27\\\\=x^3-3^3\\\\=(x-3)(x^2+3x+9)$

And g(x) can be written as

$g(x)=3x-9\\=3(x-3)$

Thus, we have

$(\frac{f}{g})(x)=\frac{(x-3)(x^2+3x+9)}{3(x-3}$

On cancelling the common factors, we get

$(\frac{f}{g})(x)=\frac{1}{3}(x^2+3x+9)$

5 0

2 years ago

the sugar-sweet company is going to transport its sugar in to Market it will cost $6,500 to rent trucks plus $150 for each ton o

Inessa05 [86]

Answer:

$ 3750 = truck rental; $125 per ton of sugar transported

C is cost; S is number of tons transported

Equation relating C to S would be a linear equation like y = mx + b

C = 125S + $3750

This equation would be graphed in the first quadrant only

you would start with your y-intercept at (0, 3750)

As x increases by 1, your y increases by 125 yielding these points:

(1, 3875) (2, 4000) (3, 4125) etc.

This shows that for each increase by one ton of sugar, the cost goes up $125

Step-by-step explanation:

3 0

2 years ago

2. Determine the sum of the first 400 ODD numbers.<br><br>

il63 [147K]

Odd numbers take the form $2n-1$ , where $n\ge1$ is an integer. When $n=400$ , the last odd number would be 799. So we're adding

$S=1+3+5+\cdots+795+797+799$

By reversing the order of terms, we have

$S=799+797+795+\cdots+5+3+1$

and we can pair up terms in both sums at the same position to write

$2S=(1+799)+(3+797)+(5+795)+\cdots(795+5)+(797+3)+(799+1)$

so that we are basically adding 400 copies of 800, and from there we can find the value of the sum right away:

$2S=400\cdot800\implies S=160,000$

###

We could also make use of the formulas,

$\displaystyle\sum_{i=1}^n1=n$

$\displaystyle\sum_{i=1}^ni=\dfrac{n(n+1)}2$

We have

$S=\displaystyle\sum_{i=1}^{400}(2i-1)=2\sum_{i=1}^{400}i-\sum_{i=1}^{400}1=400(400+1)-400=400^2=160,000$

3 0

3 years ago

En mi clase hay 30 alumnos. Hoy es el cumpleaños de Marta y regala 2 piruletas de fresa a cada chica y 1 de limón a cada chico.

Alenkasestr [34]

Answer:

La respuesta es solo dividir

Step-by-step explanation:

ara que sepas que hay 30 estudiantes y que se les dieron 49 lolipops a los estudiantes y 2 se los dieron a las niñas y 1 a los niños, todo lo que tienes que hacer es dividir

5 0

2 years ago

Read 2 more answers