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seraphim [82]
3 years ago
12

Help with these questions, please!!

Mathematics
2 answers:
ivann1987 [24]3 years ago
8 0
Your rhombus is 1,960
shepuryov [24]3 years ago
6 0

Answer:

A = 94.5x cm^2

Step-by-step explanation:

To find the area of a trapezoid you have to use this equation.

A = a+b/2*h

Now plug in the numbers

12x + 15x /2*7

27x/2*7

13.5*7

94.5

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I think that the answer is 226.194 inches
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How many hours a week do you have to work to make $5000 a month?
nasty-shy [4]
It depends on how much you earn in an hour .. so for example if your earn 100$ in 1 hour so you need to work for 50 hours in total because 5000 divided the amount of money you make in a single hour which is 100 in this example will be 50 hours in total .. to get the amount of hours you need to work a week you should know that the month has 4 weeks .. so 50 divided 4 equals 12.5 hours
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Matt wants to investigate the opinions of young adults in the country, ages 18 years to 25 years, about time spent playing video
just olya [345]

Answer:

A simple random sample without replacement (SRSWOR) of the people of the country aged 18 to 25 years.

Step-by-step explanation:

Matt wants to investigate the opinions of young adults in the country, aged 18 years to 25 years about time spent playing video games. He plans to administer a survey to a sample of people. The following may be a suitable sample :-

A simple random sample without replacement (SRSWOR) of the people of the country aged 18 to 25 years.

5 0
3 years ago
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mina [271]

Answer:

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8 0
3 years ago
A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
Katyanochek1 [597]

Answer:   (0.367,\ 0.473)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} is the sample proportion, n is the sample size , z_{\alpha/2} is the critical z-value.

Given : Significance level : \alpha:1-0.99=0.01

Sample size : n= 85

Critical value : z_{\alpha/2}=2.576

Sample proportion: \hat{p}=\dfrac{36}{85}\approx0.42

Now, the  99% confidence level will be :

\hat{p}\pmz_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.42\pm(2.576)\sqrt{\dfrac{0.42(1-0.42)}{85}}\\\\\approx0.42\pm0.053\\\\=(0.42-0.053,\ 0.42+0.053)=(0.367,\ 0.473)

Hence, the  99% confidence interval estimate of the true proportion of families who own at least one DVD player is  (0.367,\ 0.473)

3 0
3 years ago
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