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3 years ago

Juan has $10. He recently got a job and now makes $9.15 an hour. He now has $760.30. How many hours has he worked?

2 answers:

8 0

Answer:
Juan has worked in a total of 82 Hours.
Step By Step Explanation:
You can find a calculator that calculates these problems on "Goo gle". Good luck.

If available, please give me a Branliest. It would be very appreciated and would help me answer more questions! Good luck. :)

marissa [1.9K]3 years ago

6 0

Im not sure if im correct but I think the answer is 82 hours.

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In how many different ways can the letters in the word PAYMENT be arranged if the letters are taken 6 at a time?

podryga [215]

Answer:

Step-by-step explanation:

PAYMENT

1234567

THERE ARE 7 ELEMENTS

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3 years ago

If allopurinol is available in 100 mg tablets, how many tablets are needed to fill a 30 day supply

kifflom [539]

100 - 30 = 70 day supply

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3 years ago

Steve can complete the 100m dash in 10 seconds while Paul can run it in 12 seconds. How does Steve's time compare to Paul's?

Lana71 [14]

Let

x---------> Steve's time

y--------> Paul's time

we know that

$x=10\ s\\y=12\ s$

$x < y$ ------> Steve is faster than Paul

Divide x by y

$\frac{10}{12}=\frac{5}{6}$

therefore

<u>the answer is the option</u>

A. Steve is 5⁄6 as fast as Paul

8 0

3 years ago

Read 2 more answers

Thomas bought a case of 6 apple juice bottles and one 3-liter bottle of orange juice. Each apple juice bottle contains 2 liters

OleMash [197]

So...
Each bottle of apple juice has 2 litters of juice, so, if he bought y bottles of apple juice, we will have to multiply.
$6*2=12$

12 liters of apple juice
3 liters of orange juice

6 0

3 years ago

A dance class consists of 22 students, of which 10 are women and 12 are men. if 5 men and 5 women are to be chosen and then pair

OverLord2011 [107]

solution:

I choose 5 women from a pool of 10 in 10C2 ways.

I choose 5 men from a pool of 12 in 12C2 ways.

So total number of ways of choosing in 10C2 x 12C2. Now I need to arrange them in 5 pairs. This is where I have a different solution. The solution says that there are 5! ways to arrange them in pairs.

But I cant seem to understand why? My reasoning is that for first pair position I need to choose 1 man from 5 and 1 woman from 5. So for the first position I have 5 x 5 choices (5 for man and 5 for woman). Similarly for the second position I have 4 x 4 choices and so on. Hence the total ways are 5! x 5!

So I calculate the total ways as 10C2 * 12C2 * 5! * 5!. Can anyone point the flaw in my reasoning for arranging the chosen men and women in pairs.

3 0

4 years ago