Answer:
x =41.18114952
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
We know the hypotenuse and adjacent sides
cos theta = adjacent / hypotenuse
cos x = 14.3/19
taking the inverse cos of each side
cos^-1 (cos x) = cos ^-1 ( 14.3/19)
x =41.18114952
Answer:
![0.67x-2=0.43](https://tex.z-dn.net/?f=0.67x-2%3D0.43)
Step-by-step explanation:
2/3 = 0.6 repeating
3/7 = 0.42857
For this case we have:
Be a function of the form ![y = f (x)](https://tex.z-dn.net/?f=y%20%3D%20f%20%28x%29)
Where:
![f (x) = \sqrt {x-5}](https://tex.z-dn.net/?f=f%20%28x%29%20%3D%20%5Csqrt%20%7Bx-5%7D)
If we want to find f (-2), we substitute
, then:
![f (-2) = \sqrt {-2-5}\\f (-2) = \sqrt {-7}](https://tex.z-dn.net/?f=f%20%28-2%29%20%3D%20%5Csqrt%20%7B-2-5%7D%5C%5Cf%20%28-2%29%20%3D%20%5Csqrt%20%7B-7%7D)
Since we have a negative root, the result will be given by complex numbers. By definition:
![\sqrt {-1} = i](https://tex.z-dn.net/?f=%5Csqrt%20%7B-1%7D%20%3D%20i)
So:
![f (-2) = \sqrt {7} i](https://tex.z-dn.net/?f=f%20%28-2%29%20%3D%20%5Csqrt%20%7B7%7D%20i)
Answer:
![f (-2) = \sqrt {7} i](https://tex.z-dn.net/?f=f%20%28-2%29%20%3D%20%5Csqrt%20%7B7%7D%20i)
Answer: 27.5625 or 27.6
Explanation:
A square has even side lengths so each side equals 5 1/4 or 5.25. So you take two sides and multiply them together. In other words, 5.25•5.25. Then you get roughly 27.6 rounded
Answer:
you can do it i belive
Step-by-step explanation: