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fomenos
3 years ago
13

Which units are being recalled? —-

Physics
1 answer:
NemiM [27]3 years ago
8 0

Answer:

a c e f

Explanation:

Start with the last year then the month. to eliminate wrong choices

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In two or more complete sentences, describe the purpose and outcome of the Miller Urey experiment.
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4 years ago
Under most conditions, except ________ change, the resistance of an object is a constant and does not depend on the amount of th
Readme [11.4K]

Answer:

Temperature change

Explanation:

4 0
4 years ago
what is the force between a 3 Coulomb charge and a 2 Coulomb charge separated by a distance of 5 meters?
Svetllana [295]
5,625 x 10 ⁻¹⁰ is <span>the force between a 3 Coulomb charge and a 2 Coulomb charge separated by a distance of 5 meters.</span>
5 0
3 years ago
One of two nonconducting spherical shells of radius a carries a charge Q uniformly distributed over its surface, the other carri
lisabon 2012 [21]

Answer:

Explanation:

A ) The spheres are non conducting , charge will not move on the surface so neutralization of charge by + ve and - ve charge is not possible. Charges will remain intact on them . The electric field inside them will be zero . Electric field outside shell  will not be spherically symmetrical . Lines of force will emanate from the surface of positively charged shell  outwardly oriented  and end at negatively charged shell .

B )

distance between the centres of spherical shell

= 2 a

potential energy of charges

= k q₁ x q₂ / R

= k x - Q x Q / ( 2a )

= - k Q²/ 2a

So work needed to separate them to infinity will be equal to

= k Q²/ 2a

6 0
3 years ago
An ice rink is 200 feet long and 85 feet wide. The four corners of the rink are rounded to a radius of 24 feet. What is the surf
Nastasia [14]

Answer:

16,506 ft²

Explanation:

There are different ways you can divide the area using rectangles and circles.  One way is to find the area of the entire width and length, then subtract the empty areas in the corners.

If we take the empty areas and put them together, we find their area is the area of a square minus the area of a circle.

A = (2r)² − πr²

A = 4r² − πr²

A = (4 − π) r²

So the area of the rink is:

A = WL − (4 − π) r²

A = (85)(200) − (4 − π) (24)²

A ≈ 16,506 ft²

5 0
3 years ago
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