All categories

3 years ago

What force is needed to accelerate an object 5 m/s if the object has a mass of 10kg?

1 answer:

6 0

The <span>force that is needed to accelerate an object 5 m/s if the object has a mass of 10kg 50N because you multiply 5 and 10</span>

You might be interested in

At a construction site, the site manager notices that a crane takes 20 seconds to lift a 500kg steel beam up to a height of 15 m

posledela

The work done is equal to the change in potential energy which is:
P.E = mgh
P.E = 500 x 9.81 x 15
P.E = 73,575 J

Power = work / time
Power = 73,575 / 20
Power = 3,700 Watts

5 0

4 years ago

Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc

kumpel [21]

Answer: $\frac{D_A}{v_B-v_A}$

Explanation:

Given

car A had a head start of $D_A$

and it starts at x=0 and t=0

Car B has to travel a distance of $D_A and d_a$

where $d_a$ is the distance travel by car A in time t

distance travel by car A is

$d_a=v_A\times t$

For car B with speed $v_B$

$d_B=D_A+d_a$

$v_B\times t=D_A+v_A\times t$

$t=\frac{D_A}{v_B-v_A}$

7 0

4 years ago

Choose the true statement concerning the mall or subatomic particles:

solniwko [45]

C is true, and just one of those has as much mass as about 1,840 electrons.

4 0

3 years ago

Read 2 more answers

Se lanza una pelota de béisbol desde la azotea de un edificio de 25 m de altura con velocidad inicial de magnitud 10 m/s y dirig

MissTica

Answer:

v_f = 24.3 m / s

Explanation:

A) In this exercise there is no friction so energy is conserved.

Starting point. On the roof of the building

Em₀ = K + U = ½ m v₀² + m g y₀

Final point. On the floor

Em_f = K = ½ m v_f²

Emo = Em_g

½ m v₀² + m g y₀ = ½ m v_f²

v_f² = v₀² + 2 g y₀

let's calculate

v_f = √(10² + 2 9.8 25)

v_f = 24.3 m / s

6 0

3 years ago

What is a horizontal segment meaning on a position vs. time graph?

sergeinik [125]

The velocity of the object is zero (the object is at rest)

Explanation:

A position vs time graph represents the motion of an object; in particular:

The position of the object x(t) is represented on the y-axis
The time t is represented on the x-axis

For a position-time graph, the slope of the graph is given by

$m=\frac{\Delta x}{\Delta t}$

where

$\Delta x$ is the change in position

$\Delta t$ is the change in time

However, we see that this is equivalent to the definition of velocity:

$v=\frac{\Delta x}{\Delta t}$

Therefore, the slope of a position-time graph is equivalent to the velocity of the object.

And so, a horizontal segment on a position vs time graph means that the object has zero velocity (because the slope is zero).

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

4 0

4 years ago