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svetlana [45]
3 years ago
5

What force is needed to accelerate an object 5 m/s if the object has a mass of 10kg?

Physics
1 answer:
nevsk [136]3 years ago
6 0
The <span>force that is needed to accelerate an object 5 m/s if the object has a mass of 10kg 50N because you multiply 5 and 10</span>
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Parallel Plates Consider a very large conducting plate at potential V0 suspended a distance d above a very large grounded plane.
velikii [3]

Answer:

V = \frac{V_0x}{d}

Explanation:

Since the field lines are parallel and the electric field is uniform between two parallel plates, a test charge would experience the same force of attraction or repulsion no matter where it is located in the field,

I attached an image that could help to understand the representation of the field. The formula used to calculate it is given by,

E= -\frac{\Delta V}{x} (1)

If we want to consider the change in Voltage with respect to the position then it would be,

E= -\frac{dV}{dx}

According to the information provided, the potential is V_0 and there is a distance d, therefore

E= -\frac{V_0}{d} (2)

Taking equation (1) we can clear V, to what we have,

\frac{dV}{dx} = -E

dV = -Edx

Integrating,

V= - \int Edx

Substituting (2)

V = -\int \frac{V_0}{d} dx

V = \frac{V_0x}{d}

Where x is the height from the grounded plate.

8 0
3 years ago
A mass that weight stretches a spring . The system is acted on by an external force . If the mass is pushed up and then released
olchik [2.2K]

Answer:

x = A cos wt

Explanation:

To determine the position we are going to solve Newton's second law

             F = m a

           

Spring complies with Hooke's law

          F = -k x

And the acceleration of defined by

          a = d²x / dt²

         

We substitute

        - k x = m d²x / dt²

         dx² / dt² + k/m  x = 0

Let's call

           w² = k / m

The solution to this type of differential equation is

           x = A cos (wt + Ф)

Where A is the initial block displacement and the phase angle fi is determined by or some other initial condition.

In this case the body is released so that at the initial speed it is zero

From which we derive this expression

         v = dx / dt = a w sin ( wt + Ф)

         

As the System is released for t = 0 the speed is v = 0

         v = sin Ф = 0

Therefore Ф = 0

And the equation of motion is

         x = A cos wt

4 0
3 years ago
A wave that can travel only through what is a mechanical wave
WINSTONCH [101]
The answer is matter
6 0
3 years ago
At what point on a line through the ends of the meter stick is the electric field equal to zero?
Gnesinka [82]

The point on a line through the ends of the meter stick is the electric field equal to zero is 4.7 m from the 0 cm mark.

<h3>What is electric field?</h3>

An electric field is the physical field that surrounds the electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them. It also refers to physical field for a system of charged particles. Electric fields originate from the electric charges and time-varying electric currents. Electric fields and the magnetic fields are both manifestations of the electromagnetic field, one of the four fundamental interactions (also called forces) of nature.

Electric fields are important in many areas of the physics, and are exploited in electrical technology. In atomic physics and chemistry, for the instance, the electric field is the attractive force holding the atomic nucleus and electrons together in atoms. It is also force responsible for chemical bonding between atoms that result in molecules.

The electric field is defined as a vector field that associates to each point in the space the (electrostatic or Coulomb) force per unit of charge exerted on an infinitesimal positive test charge at rest at that point. The derived SI unit for electric field is the volt per meter (V/m), which is equal to the newton per coulomb (N/C)

To know more about atoms visit: brainly.com/question/1566330

#SPJ4

The correct question will be:

"A +5.00-μC point charge is placed at 0.0 cm mark of meter stick and a -4.00-μC point charge is placed at 50.0 cm mark. At what point on a line through the ends of meter stick is electric field equal to zero?"

4 0
2 years ago
Pease circle the statements incompatible with the Kelvin-Planck Statement. (A) No heat engine can have a thermal efficiency of 1
Marina86 [1]

Answer:

(C) The impossibility of having a 100% efficient heat engine is always due to friction or other dissipative effects such as the system is perfectly designed or the material needed for the system design is not available.

Explanation:

The above option was never stated in the law

8 0
3 years ago
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