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2 years ago

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The cost of three notebooks and four pencils is 8.50. The cost of final parts and eight pages is 14.50. Determine the cost of on

e notebook and the cost of one pencil?

1 answer:

Nikolay [14]2 years ago

5 0

Answer: the answ is 1 nb is 2$ and a pn is $0.50.

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Solve for x and y.<br> L<br> 60°<br> 14<br> (6x + 7y)<br> M<br> N<br> 2(2x + 1)

notsponge [240]

X=3 Y=4 is your answer

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2 years ago

In a basketball game Elena scored twice as many points as Tyler Tyler scores four points fewer than Noah and Noah scores three p

saveliy_v [14]

Full question:

In a basketball game, Elena scores twice as many points as Tyler. Tyler scores four points fewer than Noah, and Noah scores three times as many points as Mai. If Mai scores 5 points, how many points did Elena score? Explain your reasoning

Answer and explanation:

We start from known to unknown. We know that Mai scored 5 points and so we work from here.

Since Mai scored 5 points and Noah scored three times as many points then Noah's score = 3×5= 15 points

Since Tyler scored four points less than Noah, Noah's score= 15-4= 11 points

Finally Elena's score is twice that of Tyler hence Elena's score =2×11= 22 points

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2 years ago

Solve 6-7+3(-11+5)(-11+5)-5

andrew11 [14]

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2 years ago

Marine scientists categorize signature whistles of bottlenose dolphins by typelong dash—type a, type b, type c, etc. In one s

r-ruslan [8.4K]

Answer:

The 95% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 185, \pi = \frac{100}{185} = 0.5405$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123$

The 95% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

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2 years ago

The Latin Club charted a bus to travel to and participate in a state competition. The cost for each adult to ride the bus was $2

Bumek [7]

<span>a+s =17 25a + 15s = 305</span>

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2 years ago