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makvit [3.9K]
2 years ago
11

URGENT HELP PLEASE ILL GIVE BRAINIEST

Mathematics
2 answers:
hoa [83]2 years ago
7 0

Answer : 4.005 x 10 ^6

Step-by-step explanation:

10 the power of 6 is 1,000,000

If u multiply this by 4.005 you get number 2.

hope this helps : )

german2 years ago
3 0
The answer is the second one 4.005 times 10^6
You might be interested in
Solve the pair of simultaneous equations and leave the answer as a fraction in
Elena-2011 [213]

Answer:

x = 11/3 = 3 2/3

y = 13/3 = 4 1/3

Step-by-step explanation:

Here, we want to solve the system of equations simultaneously

x + y = 8

2x -3 = y

From the second equation, we have an equation for y

we can simply proceed to substitute this into the first equation

x + 2x - 3 = 8

3x - 3 = 8

3x = 8 + 3

3x = 11

x = 11/3

Recall;

y = 2x - 3

y = 2(11/3) - 3

y = 22/3 - 3

y = (22-3(3))/3

y = (22-9)/3 = 13/3

6 0
2 years ago
Find the distance between the points ( - 9, - 12) and (18, - 12)
ANTONII [103]

Hello from MrBillDoesMath!

Answer:

27



Discussion:

By the distance formula (or Pythagorean theorem)

distance =   sqrt ( (change in x)^2 + (change in y)^2)


In our case this becomes

distance =   sqrt (   (18 - (-9) )^2 + (-12 - ( -12))^2)

               =  sqrt (    ( 18 + 9) ^2   + ( -12 + 12) ^ 2)

               =  sqrt (  ( 18 + 9) ^2 + 0^2 )

               = sqrt ( 27^2)

               = 27

 

Geometrically, as both y coordinates = -12, the points define a horizontal line segment. The length is then simply the difference of the x coordinates, 18 - (-9) = 18 +9 = 27. Same answer as before



Thank you,

MrB

4 0
3 years ago
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
100 points !!!!<br> Please help ASAP: What times 28,000 equals 4,410,483,661
krok68 [10]

Answer:

157517.273607

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
MULTIPLE CHOICE QUESTION
IrinaVladis [17]

Answer:

K = 2/1

Step-by-step explanation:

Constant of proportionality can be found using any two given pair of values.

Constant of proportionality = y/x

Therefore, using (1, 2) , we have

Constant of proportionality = y/x = 2/1 = 2

Or it can be written as: k = ²/1 = 2

4 0
2 years ago
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