Answer:
- 1/64 (x+4)² (x-3) (x-4) = 0
Step-by-step explanation:
f(x) = a (x+4)²(x-3)(x-4) ... curve touch (-4,0) and not cross x axis
x=0 f(x) = -3
a (4)² * (-3) * (-4) = -3
a = - 1/64
- 1/64 (x+4)² (x-3) (x-4) = 0
Answer:
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Step-by-step explanation:
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You have the correct axis of symmetry value. Nice work.
Plug that x value into the equation to get...
y = -2x^2 - 12x - 10
y = -2*(-3)^2 - 12*(-3) - 10 <<-- replace every x with -3; then use PEMDAS
y = -2*(9) - 12*(-3) - 10
y = -18 + 36 - 10
y = 18 - 10
y = 8
The vertex is the ordered pair (-3, 8)
Note: the axis of symmetry is the vertical line through the vertex
<span>What is the slope of the line represented by the equation?
</span>C. 4/5