Temperature at noon: Tn=-2.9 f
Rate: r=+1.3 f/h
Total decreased: d=-3.7 f
Temperature at midnight: Tm=?
Tm=Tn+r(6 p.m.-12 m)+d
Tm=-2.9 f+(1.3 f/h)(18 h-12 h)+(-3.7 f)
Tm=-2.9 f+(1.3 f/h)(6 h)-3.7 f
Tm=-2.9 f+7.8 f-3.7 f
Tm=1.2 f
Answer: T<span>he temperature at midnight was 1.2 f</span>
The answer is 400 because 40.00*8.5 is 340.00. Add on the 60 dollar service charge and get 400.00.
Hope this helped :)
Add them. Pentagram interior angle is 540. 105+101+112+113=431. 540-431=109 Hence, 109 is the answer. Please brainliest.
Answer:
N = 3/8
Step-by-step explanation:
let the number be N
let's express the word sentence as a mathematical expression:
"a number multiplied by 2/5"
= "N" multiplied by 2/5
= N x (2/5)
= (2N/5) ------- (1)
"a number multiplied by 2/5 is 3/20" can be written as:
(2N/5) = 3/20 (multiplying both sides by 5)
2N = (3/20) x 5
2N = 3/4 (divide both sides by 2)
N = (3/4) ÷ 2
N = (3/4) x (1/2)
N = 3/8
For skewed data displays, the median is often a better estimate of the center of distribution than the mean because the former is unaffected by large numbers.
<h3>What is mean?</h3>
Mean refers to the average of set of two or more numbers.
Mean of a set having 'n' numbers = 
<h3>What is median?</h3>
Median refers to the middle-most value of a list of numbers, arranged either in ascending or descending order.
Median = 
Now,
- Since it takes the average of all the values in the data set, the mean is the most widely used measure of central tendency.
- Because it is unaffected by exceptionally big numbers, the median performs better than the mean when analyzing data from skewed distributions.
Hence, For skewed data displays, the median is often a better estimate of the center of distribution than the mean.
To learn more about mean and median, refer to the link:brainly.com/question/6281520
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