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givi [52]
3 years ago
14

Does anyone know the answer

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
5 0
It should be the third one
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The correlation coefficient (r) is a number that describes how closely the numbers in the data set are related. The correlation coefficient will always be between −1.0 and +1.0. If the correlation is positive, there is a positive relationship. If it is negative, the relationship is negative. If the two are not correlated at all, the correlation coefficient will be 0. Strong and weak correlations are a little more subjective in that there is no exact cutoff between strong and weak, but generally, any r value that is close to either 1 or negative 1 is considered strong. Any value of r that is closer to 0 is considered weak.



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4 years ago
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
1. Sarah has an average of 92.5 for her 3 science tests. What does she need to make on the 4th test to get a 94% average. 
zheka24 [161]
1) set up a problem
you know you want to get an avg of 94 but how do you do avg in the first place. you add up the numbers then divde by the total number of numbers used lol

so \frac{92.5+x}{2}=94
92.5 is the avg number for the last 3 tests
"x" is the 4th test score which we want to find out
"2" is the total number of numbers being added together

so now lets get x to one side

92.5+ x=94*2 (multiply 2 to both sides)
92.5+x=188
x=188-92.5  (subtract 92.5 from both sides)
x= 95.5  this is the score she need to make to avg 94%

2) you can draw a tree diagram. for example Flower1 branches off into 3 diff greens and then each of those greens branch off into 2 for with or with babies breath.

or you can simple multiply 4*3*2. you can do this because all choices are included with no restriction

your total number of options is 24
4 0
3 years ago
Find the average value of f over region
yan [13]
The area of D is given by:

\int\limits \int\limits {1} \, dA = \int\limits_0^7 \int\limits_0^{x^2} {1} \, dydx  \\  \\ = \int\limits^7_0 {x^2} \, dx =\left. \frac{x^3}{3} \right|_0^7= \frac{343}{3}

The average value of f over D is given by:

\frac{1}{ \frac{343}{3} }  \int\limits^7_0  \int\limits^{x^2}_0 {4x\sin(y)} \, dydx  = -\frac{3}{343}  \int\limits^7_0 {4x\cos(x^2)} \, dx  \\  \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49
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3 years ago
What is the following product? Assume x>/0 and y >/0. Sqrt 5x^8 y^2 • sqrt 10x^3 • sqrt 12y
Leviafan [203]

Answer: B

Step-by-step explanation:

7 0
3 years ago
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