a.
The required equation is 23p + 19.50 = 180.50
Let p represent the number of people who can go to the amusement park.
Since the ticket costs $23 per person, the total amount paid for ticket is rate × number of person = $23 × p = 23p.
Since we pay $19.50 for parking, the total amount spent is T = 23p + 19.50
Since the total amount equals $180.50. T = 180.50
So, 23p + 19.50 = 180.50
The required equation is 23p + 19.50 = 180.50
b.
Solving 23p + 19.50 = 180.50, we have
23p = 180.50 - 19.50
23p = 161
p = 161/23
p = 7
So, the number of people who can go to the amusement park is 7.
Learn more about linear equations here:
brainly.com/question/24307397
Answer:
65.91078
Step-by-step explanation:
You add the two decimals, that gives you two decimals. Use those two decimals and place them to the right of the answer. =0)
Answer:
-2l -3
Step-by-step explanation:
5l -3+ (-7)l
5l -3 -7l
5l -7l -3
-2l -3
Let the lengths of the east and west sides be x and the lengths of the north and south sides be y. the dimensions you want are therefore x and y.
The cost of the east and west fencing is $4*2*x; the cost of the north and south fencing is $2*2*y. We have to put in that "2" because there are 2 sides that run from east to west and 2 sides that run from north to south.
The total cost of all this fencing is $4(2)(x) + $2(2)(y) = $128. Let's reduce this by dividing all three terms by 4: 2x + y = 32.
Now we are to maximize the area of the vegetable patch, subject to the constraint that 2x + y = 32. The formula for area is A = L * W. Solving 2x + y = 32 for y, we get y = -2x + 32.
We can now eliminate y. The area of the patch is (x)(-2x+32) = A. We want to maximize A.
If you're in algebra, find the x-coordinate of the vertex of this quadratic equation. Remember the formula x = -b/(2a)? Once you have calculated this x, subst. your value into the formula for y: y= -2x + 32.
Now multiply together your x and y values to obtain the max area of the patch.
If you're in calculus, differentiate A = x(-2x+32) with respect to x and set the derivative equal to zero. This approach should give you the same x value as before; the corresponding y value will be the same; y=-2x+32.
Multiply x and y together. That'll give you the maximum possible area of the garden patch.
Answer:
a). The number if ways it can be arranged in a row= 362880 ways
b). 40320 ways
c). 5040 ways
Step-by-step explanation:
There are 9 alphabets in the word ALGORITHM
The number if ways it can be arranged in a row= 9!
The number if ways it can be arranged in a row= 9*8*7*6*5*4*3*2*1
The number if ways it can be arranged in a row= 362880 ways
if A and L must remain together (in order) as a unit, then we take it as 8 alphabets
= 8!
= 8*7*6*5*4*3*2*1
= 40320 ways
if the letters GOR must remain together (in order) as a unit, then we have 7 alphabets units remaining
= 7!
= 7*6*5*4*3*2*1
= 5040 ways
