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3 years ago

What is the distance from X to Y?

Mathematics

2 answers:

drek231 [11]3 years ago

7 0

***Use Pythagorean Theorem***

- Draw a line to connect them, and make it into a triangle to the y and x axis.

- count how many squares are on the outside of the lines.

- use this formula: a^2+b^2=c^2

- c^2 is what the distance that your looking for.....

- 9^2 +12^2= c^2

- 81+144=225

- square root it= 15

Answer=

B. 15 units

Rama09 [41]3 years ago

3 0

Answer:

Step-by-step explanation:

To find the distance between two points, $(A, B)$ and $(C, D)$ , you can use the following distance formula:

$distance = \sqrt{(A - C)^{2} + (B - D)^{2}}$

Plugging in the points from the problem, you'll get the following:

$\sqrt{(0 - 9)^{2} + (6 - (-6))^{2}}$

$\sqrt{(-9)^{2} + (12)^{2}}$

$\sqrt{81 + 144}$

$\sqrt{225}$

$15$

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A certain three-cylinder combination lock has 60 numbers on it. To open it, you turn to a number on the first cylinder, then

statuscvo [17]

Answer:

(a) The number of different lock combinations is 216,000.

(b) The probability of getting the correct combination in the first try is $\frac{1}{216000}$ .

Step-by-step explanation:

The lock has three-cylinder combinations with 60 numbers on each cylinder.

The procedure of the opening lock is to turn to a number on the first cylinder, then to a second number on the second cylinder, and then to a third number on the third cylinder.

The numbers can be repeated.

(a)

There are three cylinder combinations on the lock, each with 60 numbers.

It is provided that repetitions are allowed.

Then each cylinder can take any of the 60 numbers.

So there are 60 options for the first cylinder.

There are 60 options for the second cylinder.

And there are 60 options for the third cylinder.

So the total number of possible combinations is:

Total number of combinations = 60 × 60 × 60 = 216000.

Thus, the number of different lock combinations is 216,000.

(b)

The events of getting a correct combinations of the three-cylinder combination lock implies that all the three cylinder are set at the correct numbers.

Each cylinder has 60 numbers.

This implies that there are 60 possible ways to get a correct number for the first cylinder.

The probability of getting the correct number for the first cylinder is:

P (Number on 1st cylinder is correct) = $\frac{1}{60}$ .

Similarly for the second cylinder the probability of getting the correct number is:

P (Number on 2nd cylinder is correct) = $\frac{1}{60}$ .

And similarly for the third cylinder the probability of getting the correct number is:

P (Number on 3rd cylinder is correct) = $\frac{1}{60}$ .

So the probability of getting the correct combination in the first try is:

P (Correct combination in the 1st try) = $\frac{1}{60}\times \frac{1}{60}\times \frac{1}{60}=\frac{1}{216000}$ .

Thus, the probability of getting the correct combination in the first try is $\frac{1}{216000}$ .

7 0

3 years ago

HELP!!!!!

SCORPION-xisa [38]

Answer:

1, 5, 2, 4, 3, 7, 6

Step-by-step explanation:

After dividing by the leading coefficient, each equation can be put into the form ...

x² + y² + ax +by +c = 0

Subtracting c and separately completing the square for x-terms and y-terms, we get ...

x² + ax + (a/2)² + y² + by + (b/2)² = -c + (a/2)² + (b/2)²

(x +a/2)² + (y +b/2)² = r² = (a/2)² + (b/2)² -c . . . . . rewrite in standard form

Ordering by the square of the radius length will match the ordering by radius length, so we just need to compute (a/2)² +(b/2)² -c for each given equation. I find it convenient to let a calculator or spreadsheet do this calculation (see attached).

In the order the equations are given, the square of the radius is ...

3, 18, 45, 23, 5, 117, 46

So the order of the equations from smallest radius to largest is ...

1, 5, 2, 4, 3, 7, 6