If you were to befriend a person in the first 2 months of school, would you trust them, yes or no?

Mathematics

1 answer:

algol [13]3 years ago

5 0

Answer:

I guess that would depend on the type of person they are-

Step-by-step explanation:

You might be interested in

Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step

aleksandr82 [10.1K]

Answer:

Jada error was he multiplied the equation by (-9/4) to make the coefficient of x one. He should have multiplied it by 108

Step-by-step explanation:

Jada solved the equation

-4/9 = x/108

using the steps below:

-4/9 = x/108

(-4/9)(-9/4) = (x/108)(-9/4)

x = -1/48

Jada should have multiplied through by 108, instead of (-4/9). That was the error he made.

Multiplying through by 108 gives

(-4/9)(108) = (x/108)(108)

-48 = x

x = -48

The answer should have been

x = -48

and not

x = -1/48

8 0

3 years ago

Read 2 more answers

Can i have help with these questions

adell [148]

Answer:

(-3, 5), (-1, -1), (5, -3)

Step-by-step explanation:

Each pair of vertices can be one of the diagonals. Then the missing point will be found at the coordinates that are the sum of those, less the coordinates of the third point.

Given points are ...

A(-2, 2), B(1, 1), C(2, -2)

For AB a diagonal, D1 is ...

A+B-C = (-2+1-2, 2+1-(-2)) = (-3, 5)

For AC a diagonal, D2 is ...

A+C-B = (-2+2-1, 2-2-1) = (-1, -1)

For BC a diagonal, D3 is ...

B+C-A = (1+2-(-2), 1-2-2) = (5, -3)

_____

For a lot of parallelogram problems I find it easiest to work with the fact that the diagonals bisect each other. This means they both have the same midpoint, so for quadrilateral ABCD, we have (A+C)/2 = (B+D)/2. Multiplying this by 2 gives the equation we used above, A+C = B+D, so D=A+C-B. Remember, in ABCD, AC and BD are the diagonals.