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valina [46]
3 years ago
9

Can i have help with these questions

Mathematics
2 answers:
Ilya [14]3 years ago
8 0

Answer:

Answer:

 (-3, 5), (-1, -1), (5, -3)

Step-by-step explanation:

Each pair of vertices can be one of the diagonals. Then the missing point will be found at the coordinates that are the sum of those, less the coordinates of the third point.

Given points are ...

 A(-2, 2), B(1, 1), C(2, -2)

For AB a diagonal, D1 is ...

 A+B-C = (-2+1-2, 2+1-(-2)) = (-3, 5)

For AC a diagonal, D2 is ...

 A+C-B = (-2+2-1, 2-2-1) = (-1, -1)

For BC a diagonal, D3 is ...

 B+C-A = (1+2-(-2), 1-2-2) = (5, -3)

_____

For a lot of parallelogram problems I find it easiest to work with the fact that the diagonals bisect each other. This means they both have the same midpoint, so for quadrilateral ABCD, we have (A+C)/2 = (B+D)/2. Multiplying this by 2 gives the equation we used above, A+C = B+D, so D=A+C-B. Remember, in ABCD, AC and BD are the diagonals.

Thanks for everything have a good day

adell [148]3 years ago
6 0

Answer:

  (-3, 5), (-1, -1), (5, -3)

Step-by-step explanation:

Each pair of vertices can be one of the diagonals. Then the missing point will be found at the coordinates that are the sum of those, less the coordinates of the third point.

Given points are ...

  A(-2, 2), B(1, 1), C(2, -2)

For AB a diagonal, D1 is ...

  A+B-C = (-2+1-2, 2+1-(-2)) = (-3, 5)

For AC a diagonal, D2 is ...

  A+C-B = (-2+2-1, 2-2-1) = (-1, -1)

For BC a diagonal, D3 is ...

  B+C-A = (1+2-(-2), 1-2-2) = (5, -3)

_____

For a lot of parallelogram problems I find it easiest to work with the fact that the diagonals bisect each other. This means they both have the same midpoint, so for quadrilateral ABCD, we have (A+C)/2 = (B+D)/2. Multiplying this by 2 gives the equation we used above, A+C = B+D, so D=A+C-B. Remember, in ABCD, AC and BD are the diagonals.

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3 years ago
Moira said, "If a right triangle has one side with a length of 3 units and one side with a length
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3 years ago
enrollment in the ski/snowboard club increased by 30% this year. there are now 182 students in the club. how many students were
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Enrolement increased by 30% that means last year=100%
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3 years ago
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