The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
Learn more about minutes of distance apart here
brainly.com/question/8783264
Answer:
1st = 4×10 ^-9
2nd= 4×10^1
3rd = 4×10^7
4th = 4×10^-5
Step-by-step explanation:
for whole numbers you just have to count from the ending till the number indicated beside the x10
for decimals you count from the front starting at the decimal till you cover the whole number
Answer:
Shane started the problem correctly
Step-by-step explanation:
We are given problem (-5) - (-1 3/4).
Mariah started the problem as (-5) + 1 - 3/4
Shane started the problem as (-5) + 1 + 3/4
We need to find who started the problem correctly.
The problem should be started by converting the mixed fraction into improper fraction i,e
Now we will solve bracket by multiplying -1 with term inside the bracket i.e
Let's compare both the procedures now:
Mariah:
Therefore, Mariah did not start the problem correctly.
Shane:
Therefore, Shane started the problem correctly.
Answer:
Good for Megan but what’s the question?
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
2 1/2 = 5/2 = 15/6
