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deff fn [24]
3 years ago
13

A cone has a height of 2.5 in. and a radius of 5 in. What is the volume of the cone? (Use 3.14 for . Round the answer to two dec

imal places.)
32.71
65.42
196.25
588.75
Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0

Answer:

b

Step-by-step explanation:

kipiarov [429]3 years ago
6 0

Answer:

2nd option: 65.42 in³

Step-by-step explanation:

Volume of cone= \frac{1}{3}\pi {r}^{2}h

Given that the height of the cone is 2.5 in. and radius is 5 in., h= 2.5 and r= 5

Thus, volume of cone

=  \frac{1}{3} (3.14)( {5}^{2} )(2.5) \\  = 65.42 \: in^{3}  \:  \: (to \: 2 \: d.p.)

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Explain why if a runner completes a 6.2â-mi race in 32 âmin, then he must have been running at exactly 11 âmi/hr at least twice
MA_775_DIABLO [31]

Answer:

Accelerating to top speed, deaccelerating to finish line.

Step-by-step explanation:

If the runner kept a constant speed of 11 mph for the whole duration of his run (32 minutes), the distance he would have covered is:

d=11*\frac{32}{60}\\d= 5.87\ mi

This means that, in order to run the full 6.2 miles, the runner needs to reach a speed over 11 mph. Assume he starts from rest, while accelerating the runner reaches, and the surpasses, the 11 mph mark. Since his speed at the finish line is zero, the runner has to deaccelerate from his current running speed (which should be higher than 11 mph), passing through 11 mph and reaching zero at the finish line.

3 0
3 years ago
I need help with this​
zhenek [66]

Answer:

6 1/5 = 31/5 and 2 3/4 = 11/4 as improper fractions, hope this helps!

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Luzon has 8 fish, 3 cats, and 2 dogs. Write two equivalent expressions using the Associative Property that can be used to find t
ohaa [14]
8 + 3 + 2 = 13 I hope this helps
8 0
2 years ago
I do not know 6×8 is will you please help me with my homework
BartSMP [9]
If you multiply 6 times 8, you will get 48 as final answer
3 0
3 years ago
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For a fair coin, suppose you toss the coin 100 times.
Natasha_Volkova [10]

Using the normal distribution, it is found that there is a 0.0005 = 0.05% probability of getting more than 66 heads.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
  • The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with \mu = np, \sigma = \sqrt{np(1-p)}.

For the binomial distribution, the parameters are given as follows:

n = 100, p = 0.5.

Hence the mean and the standard deviation of the approximation are given as follows:

  • \mu = np = 100(0.5) = 50.
  • \sigma = \sqrt{np(1-p)} = \sqrt{100(0.5)(0.5)} = 5

Using continuity correction, the probability of getting more than 66 heads is P(X > 66 + 0.5) = P(X > 66.5), which is <u>one subtracted by the p-value of Z when X = 66.5</u>.

Z = \frac{X - \mu}{\sigma}

Z = \frac{66.5 - 50}{5}

Z = 3.3

Z = 3.3 has a p-value of 0.9995.

1 - 0.9995 = 0.0005.

0.0005 = 0.05%

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

6 0
1 year ago
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