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Alenkinab [10]
3 years ago
10

Each time a component is tested the trial is a success (S) or failure (F). Suppose the component is tested repeatedly until a su

ccess occurs on three consecutive trials. Let Y denote the number of trials necessary to achieve this. List all outcomes corresponding to the five smallest possile values of Y, and state which Y value is associated with each one.
Y Outcomes
3
4
5
6
7
Mathematics
1 answer:
babymother [125]3 years ago
4 0

Answer:

(a)\ \{SSS\}

(b)\ \{FSSS\}

(c)\ \{FFSSS, SFSSS\}

(d)\ \{FFFSSS, SSFSSS, SFFSSS, FSFSSS\}

(e)\ \{FFFFSSS, FFSFSSS, FSSFSSS, SSFFSSS, SFSFSSS, SFFFSSS, FSFFSSS\}

Step-by-step explanation:

Given

S\to Success

F\to Failure

n \to 3 Consecutive trials until S happens

Y \to Number of trials

For every possible outcome, the last 3 must be SSS. So, we have:

(a)\ Y = 3

The only possibility here is: \{SSS\}

because 3 trials implies that all outcomes must be S.

(b)\ Y = 4

The only possibility here is:

\{FSSS\}

because 4 trials implies that the first outcome must be F

 

(c)\ Y = 5

The possibilities are:

\{FFSSS, SFSSS\}

because 5 trials implies that the first and the second outcomes must be FS or SF.

(d)\ Y = 6

The possibilities are:

\{FFFSSS, SSFSSS, SFFSSS, FSFSSS\}

because 6 trials implies that the first three outcomes are: FFF, SSF and SFF

(e)\ Y = 7

The possibilities are:

\{FFFFSSS, FFSFSSS, FSSFSSS, SSFFSSS, SFSFSSS, SFFFSSS, FSFFSSS\}

because 7 trials implies that the first three outcomes are: FFFF, FSSF and SSFF and FFSF (similar to (e))

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Please Help! What is the distance between points (2, 8) and (7, 5)? Round to the nearest tenth of a unit.
zavuch27 [327]
Distance formula is like pythagoren ahtoerem
D=\sqrt{(7-2)^{2}+(5-8)^{2}}
the distance between oints (x1,y1) and (x2,y2) is
D=\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}
(2,8) and (7,5)
D=\sqrt{(7-2)^{2}+(5-8)^{2}}
D=\sqrt{(5)^{2}+(-3)^{2}}
D=\sqrt{25+9}
D=\sqrt{34}
apxos
D=5.8309....

round
D=5.8 units


6 0
3 years ago
Read 2 more answers
Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

6 0
4 years ago
Which expression is equivalent to one over fourn − 16?
ryzh [129]
The correct answer is 1/4(n - 64).

1/4n - 16  Write Original expression
0.25n -16     Simplify the fraction
0.25(n - 64)      Distribute(take out) 0.25 from n-16
1/4(n - 64)      Final Answer


I hope this helps!
8 0
3 years ago
Please help me do number 5
Blizzard [7]
Make more sense ou of this question and I can help you out more ok?
7 0
3 years ago
Please help due tommorow
raketka [301]

Answer:

4 is b 0.15

i think 5 is b

Step-by-step explanation:

i couldn't figure out the others "-u-

5 0
3 years ago
Read 2 more answers
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