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Alenkinab [10]
3 years ago
10

Each time a component is tested the trial is a success (S) or failure (F). Suppose the component is tested repeatedly until a su

ccess occurs on three consecutive trials. Let Y denote the number of trials necessary to achieve this. List all outcomes corresponding to the five smallest possile values of Y, and state which Y value is associated with each one.
Y Outcomes
3
4
5
6
7
Mathematics
1 answer:
babymother [125]3 years ago
4 0

Answer:

(a)\ \{SSS\}

(b)\ \{FSSS\}

(c)\ \{FFSSS, SFSSS\}

(d)\ \{FFFSSS, SSFSSS, SFFSSS, FSFSSS\}

(e)\ \{FFFFSSS, FFSFSSS, FSSFSSS, SSFFSSS, SFSFSSS, SFFFSSS, FSFFSSS\}

Step-by-step explanation:

Given

S\to Success

F\to Failure

n \to 3 Consecutive trials until S happens

Y \to Number of trials

For every possible outcome, the last 3 must be SSS. So, we have:

(a)\ Y = 3

The only possibility here is: \{SSS\}

because 3 trials implies that all outcomes must be S.

(b)\ Y = 4

The only possibility here is:

\{FSSS\}

because 4 trials implies that the first outcome must be F

 

(c)\ Y = 5

The possibilities are:

\{FFSSS, SFSSS\}

because 5 trials implies that the first and the second outcomes must be FS or SF.

(d)\ Y = 6

The possibilities are:

\{FFFSSS, SSFSSS, SFFSSS, FSFSSS\}

because 6 trials implies that the first three outcomes are: FFF, SSF and SFF

(e)\ Y = 7

The possibilities are:

\{FFFFSSS, FFSFSSS, FSSFSSS, SSFFSSS, SFSFSSS, SFFFSSS, FSFFSSS\}

because 7 trials implies that the first three outcomes are: FFFF, FSSF and SSFF and FFSF (similar to (e))

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Further Explanation:

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