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mina [271]
3 years ago
13

I beg for help where are the geniuses?

Mathematics
1 answer:
KatRina [158]3 years ago
7 0

Answer:

CB = sqrt62

Step-by-step explanation:

The pythagorean theorem will help with this! First take triangle ACD, AD^2 + CD^2 = AC^2. Plug in, AD^2 + 16 = 25. AD^2  = 9. AD = 3. I'm not exactly sure how to find DB, but I can assume it's double of AD< so 6. We know CD is 4, so  4^2 + 6^2 = CB^2. 16 + 36 = CB^2. CB = sqrt62

Sorry if this isn't exactly right, there's no exact way to find DB.

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Two angles are complementary. One angle is ten less than four times the other angle. Find the measure of the larger angle
Nimfa-mama [501]

Answer:

B.70

Step-by-step explanation:

For one or two angles are complementary angle(s), they have to equal 90°.

So, we need to find the larger angle, but what about the other?

Let x be the other angle and y be the angle we are looking for

x + y = 90

Lets look for x first, since one angle is ten less than four times the angle we are looking for or visa versa, we must:

y = 4x - 10

For an exchange, lets take out the y variable for another x variable:

So now we should have x + 4x - 10 = 90

Combine like terms and do cross equation :

x + 4x -10 = 90

5x - 10 = 90

Add 10 to both sides:

5x = 100

100/5 = 20

So <u><em>x=20</em></u>

<u><em></em></u>

Now for y which is what we are looking for,

y = 4x - 10

Since x is 20, plug it in

y = 80 - 10

y=70 is our larger angle

5 0
3 years ago
Help me simplify this, please!!
OlgaM077 [116]
- \sqrt[3]{2 x^{4} y^{2}  } *3 \sqrt[3]{20 x^{5}y } =-3  \sqrt[3]{2 x^{4} y^{2}20 x^{5}y} =  \\ \\ =-3 \sqrt[3]{40 x^{9}  y^{3} } =-3 \sqrt[3]{2 ^{3}*5* x^{9}  y^{3}  } = \\  \\ =-3*2 ^{ \frac{3}{3} } * x^{ \frac{9}{3} } * y^{ \frac{3}{3} }  \sqrt[3]{5} =-6 x^{3} y \sqrt[3]{5}
Answer: B.
6 0
3 years ago
Consumer Reports will have an article comparing refrigerators in the next issue. Some of the characteristics to be included in t
kap26 [50]

Answer:

brand name and model - - > CATEGORICAL

whether it has a top freezer, bottom freezer, or side-by-side LAYOUT - - > CATEGORICAL

the estimated energy consumption per year (kilowatts); - - - > QUANTITATIVE

whether or not it is Energy Star COMPLIANT - - > CAREGORICAL

the width, depth, and height in INCHES - - - > QUANTITATIVE

both the freezer and refrigerator net capacity, in cubic FEET - - - > QUANTITATIVE

Step-by-step explanation:

Given the following refrigerator characteristics :

brand name and model - - > CATEGORICAL

whether it has a top freezer, bottom freezer, or side-by-side LAYOUT - - > CATEGORICAL

the estimated energy consumption per year (kilowatts); - - - > QUANTITATIVE

whether or not it is Energy Star COMPLIANT - - > CAREGORICAL

the width, depth, and height in INCHES - - - > QUANTITATIVE

both the freezer and refrigerator net capacity, in cubic FEET - - - > QUANTITATIVE

To start with ; Categorical and quantitative variables differ most notably in the fact that, quantitative variables deals with numbers, measurements or calculated mathematical values of certain attribute in a measured species or sample. Categorical variable on the other hand mostly deals with making distinctions in properties of a sample by grouping the varibale into the different available categories based on their attributes.

6 0
3 years ago
Simplify the expression completely. 7b+3(4b−2)+6÷3
Karo-lina-s [1.5K]

Answer:

19b-4

Step-by-step explanation:

7b+3(4b-2)+6÷3

Bracket comes first so we distribute 3 over the terms in the bracket

= 7b + 12b -6 +6 ÷ 3

First we solve division

= 7b + 12b -6 +6 ÷ 3

= 7b + 12b -6 +2

= (7b+12b)+(-6+2)

= 19b -4

This can't be simplified further as it can't be solved anymore

4 0
3 years ago
Read 2 more answers
How do ypu slove dis? <br>y^2(q-4) - c(q - 4)
Annette [7]
<span><span> y2(q-4)-c(q-4)</span> </span>Final result :<span> (q - 4) • (y2 - c) </span>

Step by step solution :<span>Step  1  :</span><span>Equation at the end of step  1  :</span><span><span> ((y2) • (q - 4)) - c • (q - 4) </span><span> Step  2  :</span></span><span>Equation at the end of step  2  :</span><span> y2 • (q - 4) - c • (q - 4) </span><span>Step  3  :</span>Pulling out like terms :

<span> 3.1 </span>     Pull out     q-4 

After pulling out, we are left with : 
      (q-4) • (<span> y2</span>  *  1 +( c  *  (-1) ))

Trying to factor as a Difference of Squares :

<span> 3.2 </span>     Factoring: <span> y2-c</span> 

Theory : A difference of two perfect squares, <span> A2 - B2  </span>can be factored into <span> (A+B) • (A-B)

</span>Proof :<span>  (A+B) • (A-B) =
         A2 - AB + BA - B2 =
         A2 <span>- AB + AB </span>- B2 = 
        <span> A2 - B2</span>

</span>Note : <span> <span>AB = BA </span></span>is the commutative property of multiplication. 

Note : <span> <span>- AB + AB </span></span>equals zero and is therefore eliminated from the expression.

Check : <span> y2  </span>is the square of <span> y1 </span>

Check :<span> <span> c1  </span> is not a square !! 
</span>Ruling : Binomial can not be factored as the difference of two perfect squares

Final result :<span> (q - 4) • (y2 - c) </span><span>
</span>
4 0
3 years ago
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