Answer:
Required memory size is 16k x 8
16k = 24 x 210 = 214
Hence, No. of address lines = 14
No. of data lines = 8
a) Size of IC 1024 x 1
Total number of ICs required = 16k x 8 / 1024 x 1 = 16 x 8 = 128
b) Size of IC 2k x 4
Total number of ICs required = 16k x 8 / 2k x 4 = 8 x 2 = 16
c) Size of IC 1k x 8
Total number of ICs required = 16k x 8 / 1k x 8 = 16 x 1 = 16
Explanation:
For a, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1024 memory locations present in a IC.
For b, 11 address lines from A0 to A10 are used to select any one of the memory location out of 2k=2048 memory locations present in a IC.
For c, 10 address lines from A0 to A9 are used to select any one of the memory location out of 1k=1024 memory locations present in a IC.
Answer:
#include <iostream>
#include <cstdlib>
using namespace std;
int main() {
int[] array = new int[10];
int index = 0;
while(index < array.size()){
int number = (rand() % 100) + 1;
for (int i = 0; i < 1; i++) {
array[index] = number;
cout<< "Position "<< index << "of the array = "<< number << endl;
++index;
}
}
}
Explanation:
The while loop in the source code loops over a set of code ten times, The for loop only loops once to add the generated random number between 1 and 100 to the array of size 10. At the end of the for loop, the index location and the item of the array is printed out on the screen. The random number is generated from the 'rand()' function of the C++ standard library.
<span>Storage costs of magnetic tape are much lower than semiconductor storage (chip storage), but they take longer to access because they are not on-board the system and have to be added manually. Chip memory, on the other hand, can be used as primary storage for a system even with a higher cost because it's typically directly connected to the system board and is much more easily accessible by the system.</span>
