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zloy xaker [14]
3 years ago
7

A vehicle moves along a straight road. The vehicle's position is given by f(t) , where tt is measured in seconds since the vehic

le starts moving. During the first 10 seconds of the motion, the vehicle's acceleration is proportional to the cube root of the time since the start. Which of the following differential equations describes this relationship, where k is a positive constant?
a. df/dt = kſ
b. df/dt - = kgf
c. d²f/dt = kyt dt2
d. d²f/dt = ky
Mathematics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

Step-by-step explanation:

a

or D

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36 candy (Y) >= 0 candy(X) ----> the requirement is met.

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4 years ago
Pamela took a total of 27 quizzes over the course of 9 weeks. After attending 10 weeks of school this quarter, how many quizzes
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3 years ago
When solving a 2 step inequality, when do you flip the inequality sign, i keep getting these questions wrong, pls help, i mark b
vaieri [72.5K]
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Now to test this
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3 0
3 years ago
Which equation is best represented by the graph above (x+1)(x-3)(x+2). please explain why
Nat2105 [25]
<h3>Answer:</h3>

y = (x +2)(x -1)(x -3) . . . . or . . . . y = x³ -2x² -5x +6

<h3>Step-by-step explanation:</h3>

The graph shows y=0 at x=-2, x=1, and x=3. These are called the "zeros" or "roots" of the function, because the value of the function is zero there.

When "a" is a zero of a polynomial function, (x -a) is a factor. This means the factors of the graphed function are (x -(-2)), (x -1) and (x -3). The function can be written as the product of these factors:

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7 0
3 years ago
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