Answer:
The data are at the
<u>Nominal</u> level of measurement.
The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement.
Step-by-step explanation:
The objective here is to Identify the level of measurement of the data, and explain what is wrong with the given calculation.
a)
The data are at the <u> Nominal </u> level of measurement due to the fact that it portrays the qualitative levels of naming and representing different hierarchies from 100 basketball, 200 basketball, 300 football, 400 anything else
b) We are being informed that, the average (mean) is calculated for 597 respondents and the result is 256.1.
The given calculation is wrong because average (mean) cannot be calculated for nominal level of measurement. At nominal level this type of data set do not measure at all , it is not significant to compute their average (mean).
Answer:
Step-by-step explanation:
OS ≅ OU, so we will set those 2 expressions equal to each other and solve for y:
6y = 42 so
y = 7
Same goes for OT and OV:
x + 5 = 23 so
x = 18 and
SU = 84
Answer:
It has no value.
Step-by-step explanation:
Well, we need to consider the x and y coordinates of the giben points, and check wether the y coordinate is greater than twice the x coordinate minus 1 (i.e. 2x-1):
- For the first point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is 2, and 2>-1. So, this point is a solution.
- For the second point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 2, and 2<7. So, this point is not a solution.
- For the third point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is -10, and -10<-1. So, this point is not a solution.
- For the fourth point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 1, and 1<7. So, this point is not a solution.
I don’t quite understand this question since it’s all spaced out and there’s no picture but since domain is x/the indecent variable, “x = -6, -1, 0, 3” (the first answer choice” is correct
