If the range of the numbers in the list L is 4, then x can't be 4 since there is an element in the list that is x^2. Therefore,
0 ≤ x^2 ≤ 4 so that it would be the highest number and
0 ≤x ≤ 2
So, the value of x can be equal to 2 but not higher. So, 2 is always greater or equal to x.
Answer:
see below
Step-by-step explanation:
5x + y=10
Let x = 0 and y = 5
5*0 +5 = 10
0+5 = 10
5 =10
This is not true so (0,5) is not a solution
Answer:
-10x^2 +9+8x^2-5x+7=-2x^2-5x+16
Answer:
8 cm
Step-by-step explanation:
Answer:
check below
Step-by-step explanation:
1. c = 68-27 = 41
2. t = 7.9+1.5 =9.4
3. a = 21*3 = 63
4. (multiply whole equation by 8) 8r+6=7, r=1/8
5. x = 25.2/4.2 = 6
6. b = 75/15 = 5
7. A. 6C = 99
B. C = 99/6 = $16.50
The solution represents the cost of one ticket.
