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artcher [175]
3 years ago
5

Is 1.8L greater than 1,500 ML

Mathematics
2 answers:
Nata [24]3 years ago
8 0

Answer:

yes

Step-by-step explanation:

Dmitriy789 [7]3 years ago
8 0

Answer: yes

Step-by-step explanation: 1.8 L is greater than 1,500 ML because 1.8 L equals 1800 ML.

One Liter has 100 mL

Hope this helps :)

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Please answer correctly !!!! Will mark Brianliest !!!!!!!!!!!
vivado [14]

Step-by-step explanation:

since they are in order points p and q are in the middle and points O and R are on the end so they say that OR=36 since you don't know the exact lengths of all of the lengths in the middle from O to R then you multiply 5,6 and 1 by x and add

5x+6x+1x=12x

so then the whole length is equal to the ratio of 12x and also 36 so set those to equal each other

12x=36

x=3

so that is just the ratio and since they are asking for the length of O to Q that means that it is just 5x+6x=OQ

11x=OQ

insert x=3

33=OQ

Hope that helps :)

3 0
3 years ago
NEED HELP PLEASE!!!!!
marissa [1.9K]
A p is parrellel to T
8 0
4 years ago
I need help on this ​
Lana71 [14]

Step-by-step explanation:

it is 0.7777777778 . make sure you round it though 0.7^. or 0.78

3 0
3 years ago
Read 2 more answers
• 1 hour = 60 minutes
Nataly [62]

1 mile = 1.6 kilometers so 24*1.6 = 38.4
<em>24 miles = 38.4 kilometers</em>

1 kilometer = 1000 meters so 38.4*1000 = 38,400 meters
<em>38.4 kilometers = 38,400 meters

</em>1 hour = 60 minutes so 2*60 = 120
<em>2 hours = 120 minutes
</em>
To calculate meters per minute, divide.
38,400 / 120 = 320

So that means that Calvin's approximate speed is 320 meters per minute.

3 0
3 years ago
The number of surface flaws in plastic panels used in the interior of automobiles has a Poisson distribution with a mean of 0.08
kvv77 [185]

Answer:

a) 44.93% probability that there are no surface flaws in an auto's interior

b) 0.03% probability that none of the 10 cars has any surface flaws

c) 0.44% probability that at most 1 car has any surface flaws

Step-by-step explanation:

To solve this question, we need to understand the Poisson and the binomial probability distributions.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson distribution with a mean of 0.08 flaws per square foot of plastic panel. Assume an automobile interior contains 10 square feet of plastic panel.

So \mu = 10*0.08 = 0.8

(a) What is the probability that there are no surface flaws in an auto's interior?

Single car, so Poisson distribution. This is P(X = 0).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-0.8}*(0.8)^{0}}{(0)!} = 0.4493

44.93% probability that there are no surface flaws in an auto's interior

(b) If 10 cars are sold to a rental company, what is the probability that none of the 10 cars has any surface flaws?

For each car, there is a p = 0.4493 probability of having no surface flaws. 10 cars, so n = 10. This is P(X = 10), binomial, since there are multiple cars and each of them has the same probability of not having a surface defect.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 10) = C_{10,10}.(0.4493)^{10}.(0.5507)^{0} = 0.0003

0.03% probability that none of the 10 cars has any surface flaws

(c) If 10 cars are sold to a rental company, what is the probability that at most 1 car has any surface flaws?

At least 9 cars without surface flaws. So

P(X \geq 9) = P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}.(0.4493)^{9}.(0.5507)^{1} = 0.0041

P(X = 10) = C_{10,10}.(0.4493)^{10}.(0.5507)^{0} = 0.0003

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.0041 + 0.0003 = 0.0044

0.44% probability that at most 1 car has any surface flaws

5 0
3 years ago
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