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Ray Of Light [21]
2 years ago
6

The distance from the Earth to the Moon is 384 000 km. Work out the time it would take a car travelling at 100 km/h to travel 38

4 000 km. Give your answer in days
(Show your working out)
Mathematics
1 answer:
suter [353]2 years ago
8 0

Answer:

3840

Step-by-step explanation:

thbyrtjnbyj

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The volume of a cylinder is 81 cubic feet. What is the volume of a cone that fits exactly inside the cylinder? Provide an explan
expeople1 [14]
V ( cylinder ) = r² π h
V ( cone ) = 1/3 r² π h
A cone that fits exactly inside the cylinder has the volume:
V ( cone ) = 1/3 V ( cylinder = 1/3 · 81 = 27 ft³
8 0
3 years ago
Please help!! I’ve been struggling for days.
Tomtit [17]

Answer:

y=-1/4x-6

Step-by-step explanation:

y intercept is -6 and slope is -1/4

point slope is y-y1=m(x-x1)

you can use and point. i am using (0,-6)

y--6=-1/4(x-0)

y+6=-1/4x

-6 -6

y=-1/4x-6

7 0
2 years ago
Kevin is 3 times as old as Daniel. 4 years ago, Kevin was 5 times as old as Daniel.
rusak2 [61]

Answer:

24

Step-by-step explanation:

4 years ago, Daniel would've been 4 and Kevin would be 20, so Kevin would've been 5 times as old as Daniel. And 8 x 3 = 24. So, Kevin is 24.

4 0
3 years ago
Read 2 more answers
Whitch ordered pairs are solutions to the inequality y-4x≤-6
konstantin123 [22]

Answer:

y </ 4x - 6

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/
VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

A = \frac{1}{2}bh   (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)

We can find the base by solving equation (1) for b:

b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)

\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min    

         

Therefore, the base is decreasing at 2 cm/min.

               

I hope it helps you!  

7 0
2 years ago
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