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Ray Of Light [21]
2 years ago
6

The distance from the Earth to the Moon is 384 000 km. Work out the time it would take a car travelling at 100 km/h to travel 38

4 000 km. Give your answer in days
(Show your working out)
Mathematics
1 answer:
suter [353]2 years ago
8 0

Answer:

3840

Step-by-step explanation:

thbyrtjnbyj

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8 0
3 years ago
Lainey bought a set of 20 markers for $6 dollar sign, 6. What is the cost of 1 marker?
marin [14]
Hello!

To find the price of one marker you divide the price paid by the amount of markers bought

6 / 20 = 0.30

A marker cost $0.30

The answer is $0.30

Hope this helps!
5 0
3 years ago
Read 2 more answers
What is the value of x in trapezoid ABCD
statuscvo [17]
So the trapezoid has 2 parallel sides making segments AD and BC  transversals

Therefore making angle c and angle b add up to 180

(180-3x) + 3x + 180-9x +9x

180 +12x = 360

180= 12x
x= 15

5 0
3 years ago
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Please Answer ASAP
Masteriza [31]

hence, the common ratio of the given G.P. is 3 or −3.

6 0
3 years ago
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Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and
ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

b)

P(X1+X2 = 1 | X2 = 0) =  np(1-p)ⁿ¹⁻¹

P(X1+X2 = 1| X2 = 1) = (1-p)ⁿ¹

P(X1 + X2 = 1) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

b)

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

If k = 0, then this probability is equal to P(X1 = 1) = np(1-p)ⁿ¹⁻¹

If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

P(X1+X2 = 1) = P(X1+X2 = 1| X2 = 1) * P(X2=1) + P(X1+X2 = 1| X2 = 0) * P(X2 = 0) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

4 0
3 years ago
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