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Wewaii [24]
3 years ago
8

Factorise (x - 2y)2 -5(x - 2y) + 6​

Mathematics
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

(x-2y-8)(x-2y-4)

Step-by-step explanation:

Let (x-2y) = x

x^2 -12x +32

 

Then factor the quadratic polynomial by 2 brackets factoring.

(x-8)(x-4)

Then convert x to (x-2y)

(x-2y-8)(x-2y-4)

You might be interested in
About 7% of the population has a particular genetic mutation. 400 people are randomly selected. Find the standard deviation for
Deffense [45]

Answer:

5.10 people

Step-by-step explanation:

Calculation to Find the standard deviation for the number of people with the genetic mutation

Using this formula

Standard deviation = √ ( n * p * q)

Where,

n = 400

p = .07

q = 100%-7% = 93% or .93

Let plug in the formula

Standard deviation =√400*07*.93

Standard deviation =√26.04

Standard deviation = 5.10 people

Therefore the standard deviation for the number of people with the genetic mutation is 5.10 people.

5 0
3 years ago
What is 3 ^9? how to solve?
Tanya [424]
3⁹ is the same as doing:

3 * 3 * 3 * 3 * 3 * 3 * 3 * 3 * 3

What I would do it is narrow it down piece by piece. 

3 * 3 * 3 = 27. Do that 3 times, now you are left with:

27 * 27 * 27

27 * 27 or 27² = 729.

That leaves you with:

729 * 27

You can multiply by hand or use a calculator to get your answer of 19683.

To check your answer, plug 3⁹ into a calculator. Your answer should match this. 
7 0
4 years ago
How does solving linear inequalities compare with solving linear equations?
maks197457 [2]
It is just the difference between the signs
3 0
4 years ago
Help ASAP if u can ?
scoundrel [369]

Answer:

7 and -8

Step-by-step explanation:

A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4x).

8 0
3 years ago
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
astra-53 [7]

Answer:

3\pi \rightarrow y=2\cos \dfrac{2x}{3}\\ \\\dfrac{2\pi }{3}\rightarrow y=6\sin 3x\\ \\\dfrac{\pi }{3}\rightarrow  y=-3\tan 3x\\ \\10\pi \rightarrow y=-\dfrac{2}{3}\sec \dfrac{x}{5}

Step-by-step explanation:

The period of the functions y=a\cos(bx+c) , y=a\sin(bx+c), y=a\sec (bx+c) or y=a\csc(bx+c) can be calculated as

T=\dfrac{2\pi}{b}

The period of the functions y=a\tan(bx+c) or y=a\cot(bx+c) can be calculated as

T=\dfrac{\pi}{b}

A. The period of the function y=-3\tan 3x is

T=\dfrac{\pi}{3}

B. The period of the function y=6\sin 3x is

T=\dfrac{2\pi}{3}

C. The period of the function y=-4\cot \dfrac{x}{4} is

T=\dfrac{\pi}{\frac{1}{4}}=4\pi

D. The period of the function y=2\cos \dfrac{2x}{3} is

T=\dfrac{2\pi}{\frac{2}{3}}=3\pi

E. The period of the function y=-\dfrac{2}{3}\sec \dfrac{x}{5} is

T=\dfrac{2\pi}{\frac{1}{5}}=10\pi

5 0
4 years ago
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