To find the answer,we can divide the arches(210) bythe amount a cattle need( 1/3):
210÷1/3
=210×3
=630
Therefore, the farmland could support 630 cattles.
Hope it helps!
3b - 7u -5
Add them together and put them in alphabetical order.
54-6 = 48
48/4 (Alex-twice, Jennifer, Shannon)
48/4= 12
Alex- 12 x 2 = $24
Jennifer- 12 = $12
Shannon- 12+6 (the 6 I subtracted 54-6) = $18