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2 years ago

5

The library is to be given 5 books as a gift. The books will be selected from a list of 23 titles. If each book selected must ha

ve a different title, how many possible selections are there?

2 answers:

Arlecino [84]2 years ago

7 0

Answer:

u will try urself ......okay ...

...

Illusion [34]2 years ago

6 0

Answer:

Concept: Statistics

They will receive 5 books
There are 23 titles
There must be a different title each time.
Hence there are 23 total selections

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Last one i need help with to move on! I have a pic of the question

adoni [48]

length = 4 yards and width = 3.5 yards

let width be w then length is 2w - 3

area = w(2w - 3) = 14 (rearrange in standard form )

2w² - 3w - 14 = 0 ← in standard form

(2w - 7 )(w + 2 ) = 0 ← in factored form

equate each factor to zero and solve for w

2w - 7 = 0 ⇒ w = 3.5

w + 2 = 0 ⇒ w = - 2

but w > 0, hence w = 3.5

width = 3.5 yards and length = (2 × 3.5 ) - 3 = 4 yards

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3 years ago

How do I do this? Brainliest for best answer!

denis-greek [22]

If you replace 2 with x you will get 1 = 1

This means the anwser is :
x = 2

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3 years ago

How many ounces of pure gold and a 16 carry the old change and it weighs 2.5 ounces

sladkih [1.3K]

Make sure the question is stated clearly

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3 years ago

Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

<u>According to the Figure Given:</u>

Total Horizontal Distance = 14 in

Length = 6 in

<u>To Find :</u>

The Area of the composite figure

<u>Solution:</u>

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

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2 years ago

Examine the intersection of these two lines:

grin007 [14]

Answer:

You can't answer this question since there is no picture. Remember though the any 2 angles that make 180 degrees or resembles a line is 180 degrees.

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3 years ago