1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sashaice [31]
3 years ago
12

(x - 3)(2x + 1)(Ax + 1) = 8x? + Bx? + Cx - 3

Mathematics
1 answer:
mariarad [96]3 years ago
3 0

Answer:

Please refer the below attachments.

Hope it helps

Please mark me as the brainliest

Thank you

You might be interested in
Which expression is equivalent to (3a)-2?<br> O<br> o<br> 3a2<br> ܝ | ܝ | ܚ| ܘ ܩ|ܛܘ
Bad White [126]
Number 1 is correct 1/9a2
6 0
3 years ago
The sum of the digits of a two-digit number is 7. If the digits are reverses, the new number is 9 more than the original number.
____ [38]

25

Step-by-step explanation

Let the ones's digit =x.

So, sum of the digits =7

Tens's digit =7−x

Original no. =10(7−x)+x=70−10x+x=70−9x

Reversed no. =10x+7−x=9x+7

2(orig no) = reversed no. −2

2(70−9x)=9x+7−2

140−18x=9x+5

27x=135

x=5

Ten's digit =7−5=2

No. =25

5 0
3 years ago
Divide. simplify your answer (2x^4-6x^3+4x^2-3x)*(2x) pls show work
denis23 [38]

Distribute

2x × 2x^4 + 2x × -6x^3 + 2x ×4x^2 + 2x × - 3x

Take out the constants

(2 × 2)xx^4 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Simplify 2 × 2 to 4

4xx^4 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Use Product Rule: x^a x^b = x^a + b

4x^1 + 4 + 2x × -6x^3 + 2x ×4x^2 + 2x × -3x

Simplify 1 + 4 to 5

4x^5 + 2x × -6x^3 + 2x × 4x^2 + 2x × -3x

Take out the constants

4x^5 + (2 × -6)xx^3 + 2x × 4x^2 + 2x × -3x

Simplify 2 × -6 to -12

4x^5 - 12xx^3 + 2x × 4x^2 + 2x × -3x

Use the Product Rule: x^a x^b = x^a + b

4x^5 - 12x^1 + 3 + 2x × 4x^2 + 2x -3x

Simplify 1 + 3 to 4

4x^4 - 12x^4 + 2x ×4x^2 + 2x × -3x

Take out the constants

4x^5 - 12x^4 + (2 × 4)xx^2 + 2x × -3x

Simplify 2 × 4 to 8

4x^5 - 12x^4 + 8xx^2 + 2x × -3x

Use the Product Rule: x^a x^b = x^a + b

4x^5 - 12x^4 + 8x^ 1 + 2 + 2x × -3x

Simplify 1 + 2 to 3

4x^5 - 12x^4 + 8x^3 + 2x × -3x

Take out the constants

4x^5 - 12x^4 + 8x^3 + (2 × -3)xx

Simplify 2 × -3 to -6

4x^5 - 12x^4 + 8x^3 - 6xx

Use the Product Rule: x^a x^b = x^a + b

<u>4x^5 - 12x^4 + 8x^3 - 6x^2</u>

8 0
3 years ago
Read 2 more answers
A regular four-sided die and a regular eight-sided die are rolled to form a sum. a) Determine the probability distribution for t
White raven [17]

Answer:

4+8=12 so,if its 12 so

Step-by-step explanation:

the some will be 12

12-8=4

12-4=8

8 0
3 years ago
What is a complex fraction?
MA_775_DIABLO [31]
A comlex fraciton is a fraction with another fraction in either the denomenator or the numerator (yo dawg, I heard you like fractions...)


example

\frac{\frac{2}{3}}{\frac{6}{5}} or
\frac{\frac{2}{3}}{6} or
\frac{2}{\frac{6}{5}}
7 0
3 years ago
Other questions:
  • One hundred eight Americans were surveyed to determine the number of hours they spend watching television each month. It was rev
    10·2 answers
  • What happens when u have choice between 6n-1=4n-5
    5·1 answer
  • How do I find the area and perimeter of this circle with the given information?
    8·1 answer
  • Anton put 35 marbles equally into 5 jars. each jar holds either 5 large marbles or 7 small marbles. what size of marbles did Ant
    8·1 answer
  • Isabel joins a service to download movies. She pays $2 per movie, but she gets the first 5 movies for free. How many movies, m,
    13·2 answers
  • Brianna has 4 pink bracelets . One third of all her bracelets are pink. How many bracelets does Brianna have?
    15·1 answer
  • E(t)E, left parenthesis, t, right parenthesis models the daily amount of energy (in kilojoules, \text{kJ}kJstart text, k, J, end
    7·2 answers
  • I need help someone please help me ​
    10·1 answer
  • I needs help please, a step by step answer
    13·2 answers
  • Is the Inequality always, sometimes, or never true? -6(2x-10)+12x less than or equal to 180
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!