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natima [27]
3 years ago
7

Which of the following are solutions to the equation below?

Mathematics
1 answer:
Dovator [93]3 years ago
6 0

Answer:

Apply quaratic equation

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Factor completely 2x^3 + 14x^2 + 6x + 42.
masha68 [24]
Hello,

2x^3+14x^2+6x+42=2x^2(x+7)+6(x+7)
=(x+7)(2x²+6)
=2(x+7)(x²+3)  in IR.

or In C  2(x+7)(x-i√3)(x+i√3)
4 0
4 years ago
Pam and Chris found a home for which they would have to borrow H dollars. If they take out a 25-year loan with monthly payment M
Mariana [72]
The amount of money borrowed is $ H
Time for borrowing is 25 years
Amount paid per month M
Amount paid per year 12M
Interest rate paid=I
Let the payment method be simple interest method, then:
I=(PRT)/100
plugging in our values we have:
I=(H×R×M)/100
hence:
I=HRM/100

5 0
3 years ago
CUA ES EL 35% DE 154?
Alex Ar [27]
El 35% de 154 es 53.9

6 0
3 years ago
Read 2 more answers
Use the property of exponents to rewrite the expression<br> (-4qr)(-4qr)(-4qr)(-4qr)
ivanzaharov [21]

Answer:

(-4qr)^4

Step-by-step explanation:

(-4qr)(-4qr)(-4qr)(-4qr)

There are 4 sets of -4qr being multiplied together

(-4qr)^4

5 0
3 years ago
(Divide the following polynomials (x5 + y5) ÷ (x + y)
stiks02 [169]

\text{Use}\ a^5+b^5=(a + b) (a^4 - a^3 b + a^2 b^2 - a b^3 + b^4).\\\\(x^5+y^5):(x+y)=\dfrac{x^5+y^5}{x+y}=\dfrac{(x+y)(x^4-x^3y+x^2y^2-xy^3+y^4)}{x+y}\\\\=\boxed{x^4-x^3y+x^2y^2-xy^3+y^4}

7 0
4 years ago
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