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amid [387]
3 years ago
12

51. (08.02 MC) Box A has a volume of 48 cubic meters. Box B is similar to box A. To create Box B, Box A's dimensions were double

d. What is the volume of Box B? (1 point)
Mathematics
1 answer:
Vanyuwa [196]3 years ago
7 0

Answer:

384 m³

Step-by-step explanation:

Let the dimension of box a be l,b, and h.

ATQ,

lbh = 48 .....(1)

If we double the dimension of box A, we get box B whose new dimensions will be 2l,2b and 2h.

Let V be the volume of box B.

V = (2l)(2b)(2h)

V = 8(lbh)

= 8(48) [from equation (1)]

= 384 m³

Hence, the volume of the box B is 384 m³.

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1. Determine el valor de W en las proporciones siguientes:<br> a) (12/w) = (4/3); w =
8090 [49]

Aplicando multiplicación cruzada, tiene-se que el valor de w es w = 9.

  • Cuando una proporción es dada, con una igualdade de duas proporciones, puede-se aplicar multiplicación cruzada entre ellas.

En este problema, la ecuación que relaciona las proporciones es dada por:

\frac{12}{w} = \frac{4}{3}

Aplicando multiplicación cruzada:

4w = 12(3)

4w = 36

w = \frac{36}{4}

w = 9

El valor de w es w = 9.

Un problema similar es dado en brainly.com/question/24615636

6 0
2 years ago
PLZ help me fast 2 mins left
jek_recluse [69]

Answer:

\sqrt{-5}=i\sqrt{5}

\sqrt{-25}=5i

Step-by-step explanation:

i is an imaginary unit, this means

i^2=-1

Rewrite -5 as 5\cdot (-1)=5\cdot i^2,

then

\sqrt{-5}=\sqrt{5i^2}=\sqrt{5}\cdot \sqrt{i^2}=\sqrt{5}\cdot i=i\sqrt{5}

Rewrite -25 as -25=25\cdot (-1)=25\cdot i^2,

then

\sqrt{-25}=\sqrt{25\cdot i^2}=\sqrt{25}\cdot \sqrt{i^2}=5\cdot i=5i

6 0
3 years ago
Four posters cost $19.20. How many posters can you buy for $48.00?
stich3 [128]
You can buy 8 posters with 48.00 19.20x2=38.40 the leftover change isn’t enough to buy more
8 0
3 years ago
Jim had some dimes, quarters, and nickels. First, he counted only the dimes and quarters and found that he had 9 coins. Then, he
Olegator [25]

Answer:

$1.90

Step-by-step explanation:

Represent the numbers of nickels, dimes and quarters by n, d and q.

Then: d + q = 9, or q = 9 - d.

Also, n + d = 10

Lastly, n + d + q = 15.

Let's substitute 9 - d for q in the equation immediately above:

n + d + (9 - d) = 15, or n + 9 = 15.  Then n must be 6.

In summary, Jim has 6 nickels, (10 - 6) dimes and (9 - 4) quarters, or:

                                    6 nickels, 4 dimes and 5 quarters

Thus, he has 5($0.05) + 4($0.10) + 5($0.25), or

                         $0.25   +   $0.40   + $1.25, or          $1.90

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